相关疑难解决方法(0)

回调函数array_filter()只传递数组的值,而不传递键.

如果我有:

$my_array = array("foo" => 1, "hello" => "world");

$allowed = array("foo", "bar");

删除$my_array不在$allowed数组中的所有键的最佳方法是什么？

期望的输出:

$my_array = array("foo" => 1);

我有一个像这样的数组:

array( array(), array(), array(), array() );

主数组中的数组包含4个键及其值.所有数组中的键都是相同的,如下所示:

array( 'id' => 'post_1',
       'desc' => 'Description 1',
       'type' => 'type1',
       'title' => 'Title'
     );

array( 'id' => 'post_2',
       'desc' => 'Description 2',
       'type' => 'type2',
       'title' => 'Title'
     );

所以我想创建另一个数组并提取id和type值并将它们放在一个新数组中,如下所示:

array( 'post_1' => 'type1', 'post_2' => 'type2'); // and so on

此数组中的键将是id键旧数组的值,它们的值将是type键的值.

那么有可能实现这一目标吗？我试过搜索php.net数组函数,但我不知道使用哪个函数？

当我使用多列的pluck时,我得到这个:

{"Kreis 1 \/ Altstadt":"City","Kreis 2":"Enge","Kreis 3":"Sihifeld","Kreis 4":"Hard","Kreis 5 \/ Industriequartier":"Escher Wyss","Kreis 6":"Oberstrass","Kreis 7":"Witikon","Kreis 8 \/ Reisbach":"Weinegg","Kreis 9":"Altstetten","Kreis 10":"Wipkingen","Kreis 11":"Seebach","Kreis 12 \/ Schwamendingen":"Hirzenbach"

但我需要这个吗？

["Rathaus","Hochschulen","Lindenhof","City","Wollishofen","Leimbach","Enge","Alt-Wiedikon","Friesenberg","Sihifeld","Werd","Langstrasse","Hard","Gewerbechule","Escher Wyss","Unterstrass","Oberstrass","Fluntern","Hottingen","Hirslanden","Witikon","Seefeld","M\u00fchlebach","Weinegg","Albisrieden","Altstetten","H\u00f6ngg","Wipkingen","Affoltern","Oerlikon","Seebach","Saatlen","Schwamendingen-Mitte","Hirzenbach"]

任何建议我怎么能这样做？这是我的方法:

    public function autocomplete_districts(Request $request)
   {
      $district = $request->input('query');
      // $ass = /DB::table('districts')->select(array('district', 'region'))->get();
      // dd($ass);
      $data = Districts::whereRaw('LOWER(district) like ?', [strtolower('%'.$district . '%')])->orWhereRaw('LOWER(region) like ?', [strtolower('%'.$district . '%')])->pluck('region','district');

      return response()->json($data);
   }

我有一个简单的二维数组,如下所示:

Array
    (
        [0] => Array
            (
                [0] => abc
                [1] => 123
                [2] => aaaaa

            )

        [1] => Array
            (
                [0] => def
                [1] => 456
                [2] => ddddd
            )

        [2] => Array
            (
                [0] => ghi
                [1] => 789
                [2] => hhhhhhh
            )
    )

我正在尝试编写一个有效的函数,它将返回一个只包含每个子数组的第一个'n'列的数组.换句话说,如果n = 2,那么返回的数组将是:

Array
    (
        [0] => Array
            (
                [0] => abc
                [1] => 123


            )

        [1] => Array
            (
                [0] => def
                [1] => 456

            )

        [2] => Array
            (
                [0] => ghi …