相关疑难解决方法(0)

我有以下代码.

#include <iostream>

int * foo()
{
    int a = 5;
    return &a;
}

int main()
{
    int* p = foo();
    std::cout << *p;
    *p = 8;
    std::cout << *p;
}

而代码只是运行而没有运行时异常!

输出是 58

怎么会这样？本地变量的内存不能在其功能之外无法访问吗？

有这样的代码:

#include <iostream>

int main(){
  unsigned int* wsk2 = new unsigned int(5);
  std::cout << "wsk2: " << wsk2 << " " << *wsk2 << std::endl;
  delete wsk2;
  wsk2 = new unsigned int;
  std::cout << "wsk2: " << wsk2 << " " << *wsk2 << std::endl;
  return 0;
}

结果:

wsk2: 0x928e008 5
wsk2: 0x928e008 0

我读过new没有用零初始化内存.但似乎它确实如此.它是如何工作的？

我写了一个简单的,工作的俄罗斯方块游戏,每个块作为类单块的一个实例.

class SingleBlock
{
    public:
    SingleBlock(int, int);
    ~SingleBlock();

    int x;
    int y;
    SingleBlock *next;
};

class MultiBlock
{
    public:
    MultiBlock(int, int);

    SingleBlock *c, *d, *e, *f;
};

SingleBlock::SingleBlock(int a, int b)
{
    x = a;
    y = b;
}

SingleBlock::~SingleBlock()
{
    x = 222;
}

MultiBlock::MultiBlock(int a, int b)
{
    c = new SingleBlock (a,b);
    d = c->next = new SingleBlock (a+10,b);
    e = d->next = new SingleBlock (a+20,b);
    f = e->next = new SingleBlock (a+30,b);
}

我有一个扫描完整行的函数,并运行删除相关的块的链接列表并重新分配 - >下一个指针. …