相关疑难解决方法(0)

我试图使用python从Lambda函数更新Redshift.为此,我试图合并两个代码片段.当我单独运行它们时,两个片段都是有效的.

1. 从PyDev for Eclipse更新Redshift

   import psycopg2
   
   conn_string = "dbname='name' port='0000' user='name' password='pwd' host='url'"
   conn = psycopg2.connect(conn_string)
   
   cursor = conn.cursor()
   
   cursor.execute("UPDATE table SET attribute='new'")
   conn.commit()
   cursor.close()
   

   Run Code Online (Sandbox Code Playgroud)

2. 接收上载到S3存储桶的内容(Lambda上可用的预制模板)

   from __future__ import print_function
   
   import json
   import urllib
   import boto3
   
   print('Loading function')
   
   s3 = boto3.client('s3')
   
   
   def lambda_handler(event, context):
       #print("Received event: " + json.dumps(event, indent=2))
   
       # Get the object from the event and show its content type
       bucket = event['Records'][0]['s3']['bucket']['name']
       key = urllib.unquote_plus(event['Records'][0]['s3']['object']['key']).decode('utf8')
   
       try:
           response = s3.get_object(Bucket=bucket, Key=key)
           print("CONTENT TYPE: " + response['ContentType'])
           return response['ContentType'] …

   Run Code Online (Sandbox Code Playgroud)