我有2个列表:
List<String> subjectArr = Arrays.asList<String>("aa", "bb", "cc");
List<Long> numArr = Arrays.asList<Long>(2L, 6L, 4L);
Run Code Online (Sandbox Code Playgroud)
如何创建新的List和拉链两个列表?
List<?> subjectNumArr = zip(subjectArr, numArr);
// subjectNumArr == [{'aa',2},{'bb',6},{'cc',4}]
Run Code Online (Sandbox Code Playgroud) 使用Google Guava(Google Commons),有没有办法将两个大小相同的列表合并到一个列表中,新列表包含两个输入列表的复合对象?
例:
public class Person {
public final String name;
public final int age;
public Person(String name, int age) {
this.name = name;
this.age = age;
}
public String toString() {
return "(" + name + ", " + age + ")";
}
}
Run Code Online (Sandbox Code Playgroud)
和
List<String> names = Lists.newArrayList("Alice", "Bob", "Charles");
List<Integer> ages = Lists.newArrayList(42, 27, 31);
List<Person> persons =
transform with a function that converts (String, Integer) to Person
System.out.println(persons);
Run Code Online (Sandbox Code Playgroud)
输出:
[(Alice, 42), (Bob, 27), (Charles, 31)]
Run Code Online (Sandbox Code Playgroud)