相关疑难解决方法(0)

是否有可能解构一个未从方法返回的元组,但是是一个out参数？我不确定我是正确表达自己还是使用正确的术语,所以这里有一些例子:

void OutMethod(out (int aNumber, string someText) output)
    => output = (15, "yo");

void Usage()
{
    {
        // Works, of course.
        OutMethod(out var tuple);

        // But *slightly* aesthetically unappealing to use.
        var usage = $"{tuple.someText}: {tuple.aNumber}";
    }

    {
        // Would be awesome, but doesn't work.
        OutFunction(out var(number, text));
    }

    {
        // Would be awesome too, but doesn't work.
        OutFunction(out (var number, var text));
    }

    {
        // This doesn't work either.
        OutFunction((out var number, out var text));
    }

    {
        // Not …