当我看到这个问题的答案时,我发现我不明白自己的答案.
我真的不明白这是如何被解析的.为什么第二个示例返回False?
>>> 1 in [1,0] # This is expected
True
>>> 1 in [1,0] == True # This is strange
False
>>> (1 in [1,0]) == True # This is what I wanted it to be
True
>>> 1 in ([1,0] == True) # But it's not just a precedence issue!
# It did not raise an exception on the second example.
Traceback (most recent call last):
File "<pyshell#4>", line 1, in <module>
1 in ([1,0] == …Run Code Online (Sandbox Code Playgroud) 在Python 2.6中查看Queue.py,我发现这个构造我发现有点奇怪:
def full(self):
"""Return True if the queue is full, False otherwise
(not reliable!)."""
self.mutex.acquire()
n = 0 < self.maxsize == self._qsize()
self.mutex.release()
return n
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如果maxsize为0,则队列永远不会满.
我的问题是它如何适用于这种情况?如何0 < 0 == 0被认为是假的?
>>> 0 < 0 == 0
False
>>> (0) < (0 == 0)
True
>>> (0 < 0) == 0
True
>>> 0 < (0 == 0)
True
Run Code Online (Sandbox Code Playgroud) 为什么在使用括号时这些语句按预期工作:
>>> (True is False) == False
True
>>> True is (False == False)
True
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但是False当没有括号时它会返回?
>>> True is False == False
False
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