我需要调用一个Web并从我的asp.net mvc应用程序中的模型中检索结果数据.在Web上访问时,表单如下所示:
<form id="textEntryForm" name="textEntryForm" method="post" action="/project/evaluate_to_pdf">
<textarea id="p" rows="20" name="p" cols="132"/><br/>
<input type="button" value="parse" name="do_parse" onclick="new Ajax.Updater('parsedProject','/project/parse',{asynchronous:true,evalScripts:true,on404:function(e){alert('not found!')},parameters:Form.serialize(this.form)});return false"/>
<input type="button" value="evaluate_to_html" name="do_evaluate_to_html" onclick="new Ajax.Updater('parsedProject','/project/evaluate_to_html',{asynchronous:true,evalScripts:true,on404:function(e){alert('not found!')},parameters:Form.serialize(this.form)});return false"/>
<input type="button" value="evaluate" name="do_evaluate" onclick="new Ajax.Updater('parsedProject','/project/evaluate',{asynchronous:true,evalScripts:true,on404:function(e){alert('not found!')},parameters:Form.serialize(this.form)});return false"/>
<input type="button" value="evaluate to pdf source" name="do_evaluate_to_pdf_source" onclick="new Ajax.Updater('parsedProject','/project/evaluate_to_pdf_source',{asynchronous:true,evalScripts:true,on404:function(e){alert('not found!')},parameters:Form.serialize(this.form)});return false"/>
<input type="submit" id="do_evaluate_to_pdf" value="evaluate_to_pdf" name="do_evaluate_to_pdf"/>
</form>
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我需要将输入的数据传递给textarea id ="p".如何添加,使用WebClient进行连接?
谢谢!
编辑这不是出于测试目的,我需要检索数据以便在我的应用程序中使用.
看了一下后,我来到了这个页面.在这里,我找到了一些代码来将C#字符串发送到PHP页面.
但是,在我自己的程序中实现它后,它不起作用.这是我的代码:
private void executesend()
{
using (WebClient client = new WebClient())
{
client.UploadString(url,"POST",keys);
}
}
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对于PHP部分,我有:
<?php
mysql_connect("localhost", "", "") or die(mysql_error()); // Connect to database server(localhost) with username and password.
mysql_select_db("dimittv89_dayz") or die(mysql_error()); // Select registration database.
$name = $_GET["message"];
if ( $_SERVER['REQUEST_METHOD'] == 'POST' )
{
$name = file_get_contents('php://input');
$opdracht = "INSERT INTO 'keys', (`key`) VALUES ('$name')";
print $name;
}
if (mysql_query($opdracht)){
echo "succesfully registerd to the melloniax u wil now be returned to our …Run Code Online (Sandbox Code Playgroud)