相关疑难解决方法(0)

我想要实现的是这样的:

>>> camel_case_split("CamelCaseXYZ")
['Camel', 'Case', 'XYZ']
>>> camel_case_split("XYZCamelCase")
['XYZ', 'Camel', 'Case']

所以我搜索并找到了这个完美的正则表达式:

(?<=[a-z])(?=[A-Z])|(?<=[A-Z])(?=[A-Z][a-z])

作为我尝试的下一个逻辑步骤:

>>> re.split("(?<=[a-z])(?=[A-Z])|(?<=[A-Z])(?=[A-Z][a-z])", "CamelCaseXYZ")
['CamelCaseXYZ']

为什么这不起作用,如何从python中的链接问题获得结果？

编辑:解决方案摘要

我用一些测试用例测试了所有提供的解决方案:

string:                 ''
AplusKminus:            ['']
casimir_et_hippolyte:   []
two_hundred_success:    []
kalefranz:              string index out of range # with modification: either [] or ['']

string:                 ' '
AplusKminus:            [' ']
casimir_et_hippolyte:   []
two_hundred_success:    [' ']
kalefranz:              [' ']

string:                 'lower'
all algorithms:         ['lower']

string:                 'UPPER'
all algorithms:         ['UPPER']

string:                 'Initial'
all algorithms:         ['Initial']

string:                 'dromedaryCase'
AplusKminus:            ['dromedary', 'Case']
casimir_et_hippolyte:   ['dromedary', …

假设我有以下字符串:

getPasswordLastChangedDatetime

我怎么能用大写字母拆分它以便我能得到:

get
Password
Last
Changed
Datetime