对我而言,a pair只是a的特例tuple,但令我惊讶的是:
pair<int, int> p1(1, 2); // ok
tuple<int, int> t1(1, 2); // ok
pair<int, int> p2={1, 2}; // ok
tuple<int, int> t2={1, 2}; // compile error
Run Code Online (Sandbox Code Playgroud)
我们{}用来初始化时为什么会有区别tuple?
我试过甚至g++ -std=c++1y但仍然有错误:
a.cc: In function 'int main()':
a.cc:9:29: error: converting to 'std::tuple<int, int>' from initializer list would use explicit constructor 'constexpr std::tuple<_T1, _T2>::tuple(_U1&&, _U2&&) [with _U1 = int; _U2 = int; <template-parameter-2-3> = void; _T1 = int; _T2 = int]'
tuple<int, int> t2={1, …Run Code Online (Sandbox Code Playgroud)