我用容器管理的安全性编写了简单的应用程序.问题是当我登录并打开另一个我注销的页面时,然后我回到第一页,我点击任何链接等或刷新页面我得到这个例外.我想这是正常的(或者可能不是:))因为我退出了会话被破坏了.我该怎么做才能将用户重定向到例如index.xhtml或login.xhtml,并使他免于看到错误页面/消息?
换句话说,如何在我退出后自动将其他页面重定向到索引/登录页面?
这里是:
javax.faces.application.ViewExpiredException: viewId:/index.xhtml - View /index.xhtml could not be restored.
at com.sun.faces.lifecycle.RestoreViewPhase.execute(RestoreViewPhase.java:212)
at com.sun.faces.lifecycle.Phase.doPhase(Phase.java:101)
at com.sun.faces.lifecycle.RestoreViewPhase.doPhase(RestoreViewPhase.java:110)
at com.sun.faces.lifecycle.LifecycleImpl.execute(LifecycleImpl.java:118)
at javax.faces.webapp.FacesServlet.service(FacesServlet.java:312)
at org.apache.catalina.core.StandardWrapper.service(StandardWrapper.java:1523)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:343)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:215)
at filter.HttpHttpsFilter.doFilter(HttpHttpsFilter.java:66)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:256)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:215)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:277)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:188)
at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:641)
at com.sun.enterprise.web.WebPipeline.invoke(WebPipeline.java:97)
at com.sun.enterprise.web.PESessionLockingStandardPipeline.invoke(PESessionLockingStandardPipeline.java:85)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:185)
at org.apache.catalina.connector.CoyoteAdapter.doService(CoyoteAdapter.java:325)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:226)
at com.sun.enterprise.v3.services.impl.ContainerMapper.service(ContainerMapper.java:165)
at com.sun.grizzly.http.ProcessorTask.invokeAdapter(ProcessorTask.java:791)
at com.sun.grizzly.http.ProcessorTask.doProcess(ProcessorTask.java:693)
at com.sun.grizzly.http.ProcessorTask.process(ProcessorTask.java:954)
at com.sun.grizzly.http.DefaultProtocolFilter.execute(DefaultProtocolFilter.java:170)
at com.sun.grizzly.DefaultProtocolChain.executeProtocolFilter(DefaultProtocolChain.java:135)
at com.sun.grizzly.DefaultProtocolChain.execute(DefaultProtocolChain.java:102)
at com.sun.grizzly.DefaultProtocolChain.execute(DefaultProtocolChain.java:88)
at com.sun.grizzly.http.HttpProtocolChain.execute(HttpProtocolChain.java:76)
at com.sun.grizzly.ProtocolChainContextTask.doCall(ProtocolChainContextTask.java:53)
at com.sun.grizzly.SelectionKeyContextTask.call(SelectionKeyContextTask.java:57)
at com.sun.grizzly.ContextTask.run(ContextTask.java:69)
at com.sun.grizzly.util.AbstractThreadPool$Worker.doWork(AbstractThreadPool.java:330)
at com.sun.grizzly.util.AbstractThreadPool$Worker.run(AbstractThreadPool.java:309)
at java.lang.Thread.run(Thread.java:619)
Run Code Online (Sandbox Code Playgroud) 我发现这篇文章对非ajax请求有用如何在JSF 2中处理会话过期和ViewExpiredException? 但是当我使用AJAX调用提交时,我无法使用它.
假设在一个primefaces对话框中,我正在使用AJAX发布一个post请求,session已经超时了.我看到我的页面卡住了.
如何解决这种情况的,这样当我POST使用AJAX,我可以重定向他对我的看法过期的页面,然后转发他类似于上面的链接解决方案登录页面?
JSF2/Primefaces/Glassfish的
我一直在看这个主题的很多帖子,但无法得到一个适用于我的案例的解决方案.
我正在使用带有JSF 2.0的Java EE 6(部署在JBoss AS 7.1上)
在我的web.xml身上:
<session-config>
<session-timeout>1</session-timeout>
</session-config>
Run Code Online (Sandbox Code Playgroud)
当会话自动超时时,我希望将用户重定向到登录页面.
我试过的:
方法1:使用过滤器
我试过以下过滤器:
@WebFilter()
public class TimeOutFilter implements Filter {
@Override
public void init(FilterConfig filterConfig) throws ServletException {
}
@Override
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException,
ServletException {
System.out.println("filter called");
final HttpServletRequest req = (HttpServletRequest) request;
final HttpSession session = req.getSession(false);
if (session != null && !session.isNew()) {
chain.doFilter(request, response);
} else {
System.out.println("Has timed out");
req.getRequestDispatcher("/logon.xthml").forward(request, response);
}
} …Run Code Online (Sandbox Code Playgroud) 在用户登录之前,如果键入xxx.detail.jsf,它将重定向到登录页面,让用户登录.这项任务已经完成.如何xxx.detail.jsf在用户成功登录后将其重定向回到?
我正在使用Eclipse Indigo,Tomcat 7和Mojarra 2.0.3.