相关疑难解决方法(0)

在Django,我到处都有记录器,目前有硬编码的名字.

对于模块级日志记录(即,在视图函数模块中),我有这样做的冲动.

log = logging.getLogger(__name__)

对于类级别的日志记录(即,在类__init__方法中),我有这样做的冲动.

self.log = logging.getLogger("%s.%s" % (
    self.__module__, self.__class__.__name__))

在我解决几十次事件之前,我正在寻找第二意见getLogger("hard.coded.name").

这会有用吗？还有其他人用同样缺乏想象力的方式命名他们的记录器吗？

此外,我应该分解并为此日志定义编写类装饰器吗？

好的,首先检查以下代码:

class DemoClass():

    def __init__(self):
        #### I really want to know if self.Counter is thread-safe. 
        self.Counter = 0

    def Increase(self):
        self.Counter = self.Counter + 1

    def Decrease(self):
        self.Counter = self.Counter - 1

    def DoThis(self):
        while True:
            Do something

            if A happens:
                self.Increase()
            else:
                self.Decrease()

            time.sleep(randomSecs)

    def DoThat(self):
        while True:
            Do other things

            if B happens:
                self.Increase()
            else:
                self.Decrease()

            time.sleep(randomSecs)

    def ThreadSafeOrNot(self):
        InterestingThreadA = threading.Thread(target = self.DoThis, args = ())
        InterestingThreadA.start()

        InterestingThreadB = threading.Thread(target = self.DoThat, args = ())
        InterestingThreadB.start()

我面临着和上面相同的情况.我真的想知道它是否是线程安全的 …

1. @Singleton装饰

我找到了一种优雅的方法来装饰Python类来实现它singleton.该类只能生成一个对象.每次Instance()调用都返回相同的对象:

class Singleton:
    """
    A non-thread-safe helper class to ease implementing singletons.
    This should be used as a decorator -- not a metaclass -- to the
    class that should be a singleton.

    The decorated class can define one `__init__` function that
    takes only the `self` argument. Also, the decorated class cannot be
    inherited from. Other than that, there are no restrictions that apply
    to the decorated class.

    To get the singleton instance, use the …