相关疑难解决方法(0)

我有一个代码,它禁用页面加载按钮,因为下拉列表的值为空.但是,当选择一个值(值来自数据库,它被填充并且它正在工作)时,该按钮仍然被禁用.

jQuery的:

<script>
    $(document).ready(function(){
        $('.send').attr('disabled',true);

        $('#kagawad').keyup(function(){
            if($(this).val() != ""){
                $('.send').attr('disabled', false);
            }
            else
            {
                $('.send').attr('disabled', true);        
            }
        })
    });
</script>

HTML:

<div class="item form-group">
    <label class="control-label col-md-3 col-sm-3 col-xs-12">Select Kagawad</label>
    <div class="col-md-9 col-sm-9 col-xs-12">
    <?php
        include 'config.php';
        $selectSql = "SELECT firstName, middleName, lastName
                    FROM table_position p
                    LEFT JOIN person r ON p.Person_idPerson = r.idPerson
                    WHERE p.bar_position =  'Barangay Kagawad' AND p.activeOrInactive =  'Active'";
                    $result = mysqli_query($conn, $selectSql);
    ?>

        <select class="form-control" id = "kagawad" name = "kagawad" required>
            <option value="">Choose...</option>
            <?php …

代码就像这样:

<select id="productextra[@count@]">
<option value="[@option_id@]">Yes</option>
<option value="[@option_id@]">No</option>
</select>

应该禁用的按钮是:添加到购物车