相关疑难解决方法(0)

class MyClass
{
public:
  ~MyClass() {}
  MyClass():x(0), y(0){} //default constructor
  MyClass(int X, int Y):x(X), y(Y){} //user-defined constructor
  MyClass(const MyClass& tempObj):x(tempObj.x), y(tempObj.y){} //copy constructor

private:
  int x; int y;
};

int main()
{
  MyClass MyObj(MyClass(1, 2)); //user-defined constructor was called.
  MyClass MyObj2(MyObj); //copy constructor was called.
}

在第一种情况下,当MyClass(1, 2)调用用户定义的构造函数并返回一个对象时,我希望MyObj调用复制构造函数.为什么它不需要为第二个实例调用复制构造函数MyClass？