相关疑难解决方法(0)

我试图使用看门狗在dir中发生任何变化时运行同步脚本(除了一个特定文件).我只是复制了自述文件中的代码(粘贴在下面),它完成了它所说的内容; 记录哪个文件已更改.

import sys
import time
import logging
from watchdog.observers import Observer
from watchdog.events import LoggingEventHandler

if __name__ == "__main__":
    logging.basicConfig(level=logging.INFO,
                        format='%(asctime)s - %(message)s',
                        datefmt='%Y-%m-%d %H:%M:%S')
    path = sys.argv[1] if len(sys.argv) > 1 else '.'
    event_handler = LoggingEventHandler()
    observer = Observer()
    observer.schedule(event_handler, path, recursive=True)
    observer.start()
    try:
        while True:
            time.sleep(1)
    except KeyboardInterrupt:
        observer.stop()
    observer.join()

我现在想要在任何变化时运行一个函数(它将整个文件夹同步到远程机器).所以我只event_handler用我自己的功能代替了.但是这给了我以下错误:

Traceback (most recent call last):
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/threading.py", line 810, in __bootstrap_inner
    self.run()
  File "/Library/Python/2.7/site-packages/watchdog/observers/api.py", line 199, in run
    self.dispatch_events(self.event_queue, self.timeout)
  File "/Library/Python/2.7/site-packages/watchdog/observers/api.py", …