相关疑难解决方法(0)

请考虑以下代码:

DummyBean dum = new DummyBean();
dum.setDummy("foo");
System.out.println(dum.getDummy()); // prints 'foo'

DummyBean dumtwo = dum;
System.out.println(dumtwo.getDummy()); // prints 'foo'

dum.setDummy("bar");
System.out.println(dumtwo.getDummy()); // prints 'bar' but it should print 'foo'

所以,我想复制dum到dumtwo并更改dum而不影响dumtwo.但上面的代码并没有这样做.当我改变某些内容时dum,也会发生同样的变化dumtwo.

我想,当我说dumtwo = dum,Java 只复制引用.那么,有没有办法创建一个新的副本dum并分配给它dumtwo？

如果Java类实现了Serializable接口但没有公共clone()方法,通常可以创建如下的深层副本:

class CloneHelper {
    @SuppressWarnings("unchecked")
    public static <T extends Serializable> T clone(T obj) {
        try {
            ByteArrayOutputStream baos = new ByteArrayOutputStream();
            ObjectOutputStream oos = new ObjectOutputStream(baos);
            oos.writeObject(obj);
            oos.close();
            byte[] bytes = baos.toByteArray();
            ByteArrayInputStream bais = new ByteArrayInputStream(bytes);
            ObjectInputStream ois = new ObjectInputStream(bais);
            T copy = (T) ois.readObject();
            ois.close();
            return copy;
        } catch (ClassNotFoundException ex) {
            // Shouldn't happen
            throw new Error(ex);
        } catch (IOException ex) {
            // Probably a bug in T's custom serialization methods
            throw …