相关疑难解决方法(0)

有没有一种简单的方法来填充我的C#对象与通过AJAX传递的JSON对象？

//这是使用JSON.stringify从页面传递给C#WEBMETHOD的JSON对象

{
    "user": {
        "name": "asdf",
        "teamname": "b",
        "email": "c",
        "players": ["1", "2"]
    }
}

// C#WebMetod接收JSON对象

[WebMethod]
public static void SaveTeam(Object user)
{

}

// C#类,表示传入WebMethod的JSON Object的对象结构

public class User
{
    public string name { get; set; }
    public string teamname { get; set; }
    public string email { get; set; }
    public Array players { get; set; }
}

我的应用程序的Release文件夹中有一个settings.json文件.我想要做的是更改它的值,而不是暂时,永久..这意味着,删除旧条目,写一个新条目并保存它.

这是JSON文件的格式

{
"Admins":["234567"],
"ApiKey":"Text",
"mainLog": "syslog.log",
"UseSeparateProcesses": "false",
"AutoStartAllBots": "true",
"Bots": [
    {
        "Username":"BOT USERNAME",
        "Password":"BOT PASSWORD",
        "DisplayName":"TestBot",
        "Backpack":"",
        "ChatResponse":"Hi there bro",
        "logFile": "TestBot.log",
        "BotControlClass": "Text",
        "MaximumTradeTime":180,
        "MaximumActionGap":30,
        "DisplayNamePrefix":"[AutomatedBot] ",
        "TradePollingInterval":800,
        "LogLevel":"Success",
        "AutoStart": "true"
    }
]
}

假设我想更改密码值而不是BOT PASSWORD我希望它只是密码.我怎么做？

我正在使用NewtonSoft JObject解析JSON字符串.如何以编程方式从动态对象获取值？我想简化代码,不要为每个对象重复自己.

public ExampleObject GetExampleObject(string jsonString)
{
ExampleObject returnObject = new ExampleObject();
dynamic dynamicResult = JObject.Parse(jsonString);
if (!ReferenceEquals(dynamicResult.album, null))
   {
       //code block to extract to another method if possible
       returnObject.Id = dynamicResult.album.id; 
       returnObject.Name = dynamicResult.album.name;
       returnObject.Description = dynamicResult.albumsdescription;
       //etc..
   }
else if(!ReferenceEquals(dynamicResult.photo, null))
   {
       //duplicated here
       returnObject.Id = dynamicResult.photo.id;
       returnObject.Name = dynamicResult.photo.name;
       returnObject.Description = dynamicResult.photo.description;
       //etc..
   }
else if..
//etc..

return returnObject;
}

有什么办法可以将"if"语句中的代码块提取到一个单独的方法,例如:

private void ExampleObject GetExampleObject([string of desired type goes here? album/photo/etc])
{
  ExampleObject returnObject = new ExampleObject(); …

我正在尝试使用vs 2012中的过去特殊功能,以便为我的Json数据生成c#类.我从Nuget从NewtonSoft下载了Json.New,然后添加了一个新的.cs类,将我的json数据复制到剪贴板,但是当我转到Edit-> Paste Special - >时,我只能看到:将XML粘贴为类只有粘贴Json as Classes功能未显示.有什么建议？提前谢谢你

这是我得到的,请注意我已经安装了Newtonsoft.Json:

http://icms.indevcogroup.com/uploads/untitled.png

可能重复:
C#中的增量JSON解析

以下问题是相关的,但不解决(至少直接)我正在尝试解决的问题:

• 将JSON数据流从文本文件加载到对象C#中
• 使用NewtonSoft将JSON反序列化为.net对象(或者可能是linq到json？)

我试图使用Json.NET反序列化可能非常大的JSON数据.JObject.Parse(JsonFullString)我希望通过令牌从流令牌中读取并构造对象图,而不是将整个文件加载到内存中并使用解析JSON .我将不胜感激任何关于如何从流实现反序列化的建议.

注意:我的意图是用更好的实现替换以下代码

      string jsonData = string.Empty;
      byte[] buffer = new byte[16 * 1024];
      using (MemoryStream ms = new MemoryStream())
      {
          int read;
          while ((read = stream.Read(buffer, 0, buffer.Length)) > 0)
          {
              ms.Write(buffer, 0, read);
          }
          jsonData = ASCIIEncoding.ASCII.GetString(ms.ToArray());
       }                    
       JObject jObject = JObject.Parse(jsonData);
       var entities = from e in jObject.Root
                      select e;

我正在尝试解析以下复杂的 JSON 结果，该结果是从 Zoho Crm API 返回的：

{
"response":
{
    "result":
    {
        "Contacts":
        {
            "row":
            [
                {
                    "no":"1",
                    "FL":
                    [
                        {
                            "content":"555555000000123456",
                            "val":"CONTACTID"
                        },
                        {
                            "content":"555555000000012345",
                            "val":"SMOWNERID"
                        },
                        {
                            "content":"John Doe",
                            "val":"Contact Owner"
                        },
                        {
                            "content":"Pete",
                            "val":"First Name"
                        },
                        {
                            "content":"Smith",
                            "val":"Last Name"
                        },
                        {
                            "content":"pete@mail.com",
                            "val":"Email"
                        },
                        {
                            "content":"5555551000000012346",
                            "val":"SMCREATORID"
                        },
                        {
                            "content":"Jane Doe",
                            "val":"Created By"
                        },
                        {
                            "content":"555555000000012347",
                            "val":"MODIFIEDBY"
                        },
                        {
                            "content":"Doris Doe",
                            "val":"Modified By"
                        },
                        {
                            "content":"2013-06-14 17:24:10",
                            "val":"Created Time"
                        },
                        {
                            "content":"2013-06-14 17:24:10",
                            "val":"Modified Time"
                        }, …

假设我有3个整数都声明为

int Y = 0;
int N = 0;
int U = 0;

从那里我从存储过程中获取2个值(一个字符串和一个整数).
该字符串返回Y,N,U
整数返回参加人数.

string test = dr["ATTEND_CDE"].ToString();
int test2 = int.Parse(dr["COUNT"].ToString());

有没有更好的方法来分配相应的整数除以下计数:

if (test == "Y")
{
    Y = test2;
}
else if (test == "N")
{
    N = test2;
}
else if (test == "U")
{
    U = test2;
}

我有以下 json：

"rates": {
        "AT": {
            "country": "Austria",
            "standard_rate": 20.00,
            "reduced_rate": 10.00,
            "reduced_rate_alt": 13.00,
            "super_reduced_rate": false,
            "parking_rate": 12.00
        },
        "DK": {
            "country": "Denmark",
            "standard_rate": 25.00,
            "reduced_rate": false,
            "reduced_rate_alt": false,
            "super_reduced_rate": false,
            "parking_rate": false
        },
}

我有以下类来反序列化 json：

    public string country { get; set; }
    public double standard_rate { get; set; }
    //public string reduced_rate { get; set; }
    private double _reduced_rate;

    public double reduced_rate
    {
        get { return _reduced_rate; }
        set
        {
            bool isDouble = Double.TryParse(value.ToString(), out _reduced_rate);
            if (isDouble) …

我正在使用C#.Net并试图解析一些JSON.

我有这个我检索的JSON.我试过使用JavaScriptSerliazer,但无法弄清楚正确的结构.

解析此JSON以获取每个数组(第一,第二,第三等)的最佳方法是什么？

{
"first":["A","B"],
"second":["C","D"],
"third":["E","F","G","H","I"],
"fourth":["J","K","L","M","N"]
}

我正在尝试使用Json.NET库读取JsonArray中包含一些值的json对象。我想将每个数组值转换成变量。以下是Json String。请指导，谢谢。

{"enad_list":
      [{
        "et_cnic":"1090202369011",
        "et_name":"Its me",
        "et_father_husband_name":"My father name",
        "et_present_add":"Its my address",
        "et_permanent_add":"Its my another address ",
        "et_date_of_birth":"10-9-1982",
        "et_birth_place":"My Birth place",
        "et_expiry_date":"2020-12-15"
       }]
}

编辑：到目前为止，我已经尝试过此代码并收到错误消息。请查看图片以了解错误

    string jsonData =@"{""enad_list"":[{""et_cnic"":""1090202369011"",""et_name"":""Its me""}]}";
    dynamic jsonData = JObject.Parse(abc.ToString());
    int cnic = jsonData.enad_list.et_cnic;

错误图片