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我尝试使用 += 运算符在 bash 中附加一个数组，但不知道为什么它不起作用

#!/bin/bash


i=0
args=()
while [ $i -lt 5 ]; do

    args+=("${i}")
    echo "${args}"
    let i=i+1

done

预期成绩

0
0 1
0 1 2
0 1 2 3
0 1 2 3 4

实际结果

0
0
0
0
0

任何帮助，将不胜感激。

I ran shellcheck on my script and ran into an error on a very simple aspect -

echo "List of fields deleted: ${deleted[@]}"
^-----------^ SC2145: Argument mixes string and array. Use * or separate argument.

I am trying to do similar behavior as below-

declare -a  deleted
deleted = ("some.id.1" "some.id.22" "some.id.333")
echo "List of fields deleted: ${deleted[@]}"

Which is a better practice to print the elements in the array?

echo "List of fields deleted: ${deleted[@]}"

OR

echo "List of …