相关疑难解决方法(0)

我有一个熊猫数据帧df.我将它分为3列,并计算结果.当我这样做时,我会丢失一些信息,特别是name列.此列与desk_id列以1:1映射.无论如何都要在我的最终数据框中包含两者吗？

这是数据帧:

   shift_id    shift_start_time      shift_end_time        name                   end_time       desk_id  shift_hour
0  37423064 2014-01-17 08:00:00 2014-01-17 12:00:00  Adam Scott 2014-01-17 10:16:41.040000  15557987           2
1  37423064 2014-01-17 08:00:00 2014-01-17 12:00:00  Adam Scott 2014-01-17 10:16:41.096000  15557987           2
2  37423064 2014-01-17 08:00:00 2014-01-17 12:00:00  Adam Scott 2014-01-17 10:52:17.402000  15557987           2
3  37423064 2014-01-17 08:00:00 2014-01-17 12:00:00  Adam Scott 2014-01-17 11:06:59.083000  15557987           3
4  37423064 2014-01-17 08:00:00 2014-01-17 12:00:00  Adam Scott 2014-01-17 08:27:57.998000  15557987           0

我这样分组:

grouped = df.groupby(['desk_id', 'shift_id', …