相关疑难解决方法(0)

我的项目中有2个Form(Form1和Form2),Form1是自动创建表单,但Form2是可用表单.我怎么能创建Form2并卸载Form1？

我在此代码中收到"访问验证"错误.

这是Form1代码:

1.  uses Unit2;
//*********
2.  procedure TForm1.FormCreate(Sender: TObject);
3.  var a:TForm2;
4.  begin
5.      a := TForm2.Create(self);
6.      a.Show;
7.      self.free;  // Or self.destory;
8.  end;

谢谢.

我将"Serg"代码修改为:

unit Unit1;

interface

uses
  Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
  Dialogs, StdCtrls;

type
  TForm1 = class(TForm)
    Button1: TButton;
    procedure Button1Click(Sender: TObject);
  private
    { Private declarations }
  public
    { Public declarations }
  end;
var
  Form1: TForm1;

implementation

uses Unit2;

{$R *.dfm}

procedure TForm1.Button1Click(Sender: TObject);
begin
  Application.CreateForm(TForm2, Form2);
  Release; …