相关疑难解决方法(0)

Android,通过HTTP POST(SOAP)发送XML

我想通过Android调用web服务.我需要通过HTTP将一些XML发布到URL.我发现这是剪辑发送POST,但我不知道如何包含/添加XML数据本身.

public void postData() {
         // Create a new HttpClient and Post Header  
         HttpClient httpclient = new DefaultHttpClient();  
         HttpPost httppost = new HttpPost("http://10.10.4.35:53011/");

         try {  
             // Add your data  
             List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);  
             nameValuePairs.add(new BasicNameValuePair("Content-Type", "application/soap+xml"));               
             httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 
                 // Where/how to add the XML data?


             // Execute HTTP Post Request  
             HttpResponse response = httpclient.execute(httppost);  

         } catch (ClientProtocolException e) {  
             // TODO Auto-generated catch block  
         } catch (IOException e) {  
             // TODO Auto-generated catch block  
         }  
     }
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这是我需要模仿的完整POST消息:

POST /a8103e90-f1e3-11dd-bfdb-8b1fcff1a110 …
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xml post android soap http

46
推荐指数
3
解决办法
9万
查看次数

Android项目使用httpclient - > http.client(apache),post/get方法

我正在为一个Android项目做一个Get和Post方法,我需要将HttpClient 3.x"翻译"到HttpClient 4.x(由android使用).我的问题是,我不确定我做了什么,我找不到某些方法的"翻译"......

这是我做过的HttpClient 3.x和( - >)HttpClient 4.x"翻译"如果我找到它(只有那些问我问题的人):

HttpState state = new HttpState (); --> ?

HttpMethod method = null; --> HttpUriRequest httpUri = null;

method.abort(); --> httpUri.abort(); //httpUri is a HttpUriRequest

method.releaseConnection(); --> conn.disconnect(); //conn is a HttpURLConnection

state.clearCookies(); --> cookieStore.clear(); //cookieStore is a BasicCookieStore

HttpClient client = new HttpClient(); --> DefaultHttpClient client = new DefaultHttpClient();

client.getHttpConnectionManager().getParams().setConnectionTimeout(SOCKET_TIMEOUT) --> HttpConnectionParams.setConnectionTimeout(param, SOCKET_TIMEOUT);

client.setState(state); --> ?

client.getParams().setCookiePolicy(CookiePolicy.RFC_2109); --> HttpClientParams.setCookiePolicy(param, CookiePolicy.RFC_2109);

PostMethod post = (PostMethod) method; --> ?

post.setRequestHeader(...,...); --> conn.setRequestProperty(...,...);

post.setFollowRedirects(false); --> …
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java android http apache-httpclient-4.x

9
推荐指数
2
解决办法
9万
查看次数

如何在Android中执行HTTP发布?

我是Android应用程序开发的新手,我需要的是我有两个文本框用户名和密码,它会发布到服务器并使用php页面检查它,如果登录成功则转到下一个屏幕,否则显示一个msg框显示登录错误我该怎么办?

public void postData() {
    // Create a new HttpClient and Post Header
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("http://google.com");
    EditText tw =(EditText) findViewById(R.id.EditText01);
    try {
        // Add your data
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        nameValuePairs.add(new BasicNameValuePair("id", "12345"));
        nameValuePairs.add(new BasicNameValuePair("stringdata", "AndDev is Cool!"));
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

        // Execute HTTP Post Request
        HttpResponse response = httpclient.execute(httppost);
        int status = response.getStatusLine().getStatusCode();

        tw.setText(status);
    } catch (ClientProtocolException e) {
        tw.setText(e.toString());
    } catch (IOException e) {
        tw.setText(e.toString());
    }
} 
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android http http-post

9
推荐指数
1
解决办法
5万
查看次数

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android ×3

http ×3

apache-httpclient-4.x ×1

http-post ×1

java ×1

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soap ×1

xml ×1