有没有办法将JSON内容反序列化为C#4动态类型?为了使用DataContractJsonSerializer,跳过创建一堆类会很不错.
我似乎无法在Visual Studio 2010中找到JavaScriptSerializer对象和System.Web.Script.Serialization命名空间.我需要将某些内容序列化为JSON我应该使用什么?
是的,我已经System.Web.Extensions在项目中包含了(在System.Web.Extensions.dll中).这让我感到震惊的原因是什么?
System.Web.Extensions被标记为过时我想将json字符串转换为Object列表.请帮我.如果完成它会更有帮助NewtonJson.
我试过了,但它不起作用.我不想要那个json的所有值.就是在MatrixModel中提到的
这是一个对象
public class MatrixModel
{
public string S1 { get; set; }
public string S2 { get; set; }
public string S3 { get; set; }
public string S4 { get; set; }
public string S5 { get; set; }
public string S6 { get; set; }
public string S7 { get; set; }
public string S8 { get; set; }
public string S9 { get; set; }
public string S10 { get; set; }
public …Run Code Online (Sandbox Code Playgroud) 大家好,我很难将下面的linq表达式(左连接实现)转换为lambda表达式(用于学习).
var result = from g in grocery
join f in fruit on g.fruitId equals f.fruitId into tempFruit
join v in veggie on g.vegid equals v.vegid into tempVegg
from joinedFruit in tempFruit.DefaultIfEmpty()
from joinedVegg in tempVegg.DefaultIfEmpty()
select new { g.fruitId, g.vegid, fname = ((joinedFruit == null) ? string.Empty : joinedFruit.fname), vname = ((joinedVegg == null) ? string.Empty : joinedVegg.vname) };
Run Code Online (Sandbox Code Playgroud)
有人可以建议我如何做到这一点.
如果有人给我"C#Lambdas&Linqs"的优秀教程链接,我真的很感激
我需要将此JSON字符串解析为我的"WeatherJson"类型的对象.但是我不知道如何解析字符串中的阵列,如"'天气’: [{"id":802,"main":"Clouds","description":"scattered clouds","icon":"03d"}].实体类会是什么样子?
JSON字符串:
{
"coord": {"lon":79.85,"lat":6.93},
"sys": {
"type": 1,
"id": 7864,
"message": 0.0145,
"country": "LK",
"sunrise": 1435883361,
"sunset": 1435928421
},
"weather": [
{"id":802, "main":"Clouds", "description":"scattered clouds", "icon":"03d"}
],
"base": "stations",
"main": {
"temp": 302.15,
"pressure": 1013,
"humidity": 79,
"temp_min": 302.15,
"temp_max": 302.15
},
"visibility":10000,
"wind": { "speed": 4.1, "deg": 220 },
"clouds": { "all": 40 },
"dt": 1435893000,
"id":1248991,
"name":"Colombo",
"cod":200
}
Run Code Online (Sandbox Code Playgroud)
编辑
我需要从代码中检索以下值:
WeatherJson w = new WeatherJson();
Console.WriteLine(w.weather.description);
//that above line was retrieved and stored …Run Code Online (Sandbox Code Playgroud)