当我AVPlayerItem(url: customUrl)从我的应用程序使用时,我得到以下运行时错误:
CredStore - performQuery - Error copying matching creds. Error=-25300, query={
class = inet;
"m_Limit" = "m_LimitAll";
"r_Attributes" = 1;
sync = syna;
}
Run Code Online (Sandbox Code Playgroud)
该错误是无害的,它只是阻止我的控制台.有趣的是我只从主应用程序中获取此错误,而不是从完全相同代码所在的键盘扩展名中获取此错误.应该注意我正在访问带有.mp3文件的https网址.任何想法如何沉默运行时错误?
错误:
CredStore - performQuery - Error copying matching creds. Error=-25300, query={
class = inet;
"m_Limit" = "m_LimitAll";
"r_Attributes" = 1;
sync = syna;
}
Run Code Online (Sandbox Code Playgroud)
当我运行该示例应用程序时,我已经下载了VGPlayerExample(https://github.com/VeinGuo/VGPlayer)pod,它正在播放所有视频但是当我添加我的URL(http://sampledomain/some/playlist.m3u8)时,它没有播放并显示上述错误.任何人都可以建议解决这个问题.
我正在尝试使用AVPlayer的子类在子视图上在我的swift应用程序上播放Vimeo视频.即使不需要凭据或登录Vimeo来查看此特定视频,当我尝试设置视频时,我收到以下错误:
CredStore - performQuery - Error copying matching creds. Error=-25300, query={
class = inet;
"m_Limit" = "m_LimitAll";
"r_Attributes" = 1;
sync = syna;
}
Run Code Online (Sandbox Code Playgroud)
在UIView上设置播放器后,我的代码非常简单:
player.set(AVURLAsset(url: URL(string: videoURLString)!))
player.play()
Run Code Online (Sandbox Code Playgroud)
关于可能出现什么问题的想法,或者如何在VC中的子视图上简单地播放Vimeo视频?
谢谢.
我正在尝试使用带有此代码的alamofire 4.7.1上传图像,但是老实说,我怀疑我没有编写正确的代码来上传图像
func uploadDefect(defectRemark: String, defectLocation: String, defectImage: UIImage, fileNameImage: String, completion: @escaping(_ errorMessage: String?) -> Void) {
guard let imgData = defectImage.jpeg(.medium) else {return}
let urlUpload = URLService.uploadDefect.endPoint
let username = "admin"
let password = "1234"
let credentialData = "\(username):\(password)".data(using: String.Encoding.utf8)!
let base64Credentials = credentialData.base64EncodedString(options: [])
let headers = ["Authorization": base64Credentials]
let parameters : [String:Any] = ["defect_remark" : defectRemark, "defect_location": defectLocation, "tenant_id" : tenantID]
let url = try! URLRequest(url: URL(string: urlUpload)!, method: .post, headers: headers)
Alamofire.upload(
multipartFormData: { multipartFormData …Run Code Online (Sandbox Code Playgroud)