我想在整个页面加载之前运行一些javascript.这可能吗?或者代码是否开始执行</html>?
我有这个代码:
<script>
function toggle(source) {
checkboxes = document.getElementsByName('DG1');
for each(var checkbox in checkboxes)
checkbox.checked = source.checked;
checkboxes = document.getElementsByName('DG2');
for each(var checkbox in checkboxes)
checkbox.checked = source.checked;
checkboxes = document.getElementsByName('DG3');
for each(var checkbox in checkboxes)
checkbox.checked = source.checked;
checkboxes = document.getElementsByName('DG4');
for each(var checkbox in checkboxes)
checkbox.checked = source.checked;
checkboxes = document.getElementsByName('DG5');
for each(var checkbox in checkboxes)
checkbox.checked = source.checked;
}
</script>
<input type="checkbox" onClick="toggle(this)" />Select All<br/>
<form method=POST action="DGUsageServlet">
<input type="checkbox" name="DG1">DG1</input>
<input type="checkbox" name="DG2">DG2</input>
<input type="checkbox" name="DG3">DG3</input>
<input …Run Code Online (Sandbox Code Playgroud) 如何获取父容器的所有后代元素?我想把它们放在阵列中.
<div class="parent">
<div class="child1">
<span class="child2">
<div class="child3">
<div class="child4">
<span class="child5"></span>
</div>
<div class="child6">
<div class="class7"></div>
</div>
</div>
</span>
<div class="child8"></div>
<span class="child9">
<div class="child10"></div>
</span>
</div>
</div>
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我认为递归是一种选择.在第一点,我知道parent元素.
我怎样才能读testArrray入 ul li 并对这个列表进行排序?
lis.sort(function(a,b))有英语/阿拉伯语/和字母支持,不支持波斯字母。请帮帮我。谢谢
var alphabets = ["?", "?", "?", "?", "?", "?", "?", "?", "?", "?", "?", "?", "?", "?", "?", "?", "?", "?", "?", "?", "?", "?", "?", "?",
"?", "?", "?", "?", "?", "?", "?", "?", "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"
];
var testArrray = ["?", "?", "?", "?"];
var aChar;
var …Run Code Online (Sandbox Code Playgroud)我需要使用Javascript删除div中具有“ item”类的所有标签,但一个标签除外<b>。
这是我的HTML文档的样子,(我的示例代码):
<div class="item">
<a href="sample-href1">
<div class="result-image">
<h5 class="result-cat cat-conf wn">test</h5>
</div>
</a>
<h4>1.
<a href="sample-href2" title="sample-title2">
<b> goal tag1 (i need just this tag) </b>
</a>
</h4>
<span class="feature">test</span>
<div class="compact">
</br>
<a href="test12" title="test12"> test12 </a>
<br>
<b> some text </b>
<a href="test123" title="test123"> test123 </a> -
<a href="test147" title="test147" > test147 </a>
</br>
<b>11</b>
another some text
</br>
</div>
<a href="test159" title="test159" class="download"> test </a>
<div class="clr"></div>
</div>
<div class="item">
<a href="sample-href1968">
<div …Run Code Online (Sandbox Code Playgroud) 我想编写一段代码,以遍历页面的document.body并报告所有空块级DOM节点。这是SEO / a11y的通行证。
我发现这篇文章似乎会有所帮助:
https://css-tricks.com/snippets/jquery/check-for-empty-elements/
$('*').each(function() {
if ($(this).is(':empty') == "") {
//Do Something
}
});
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问题1:如何转换.is(':empty')为香草js:
function isEmpty(el) {
// Robust isEmpty logic here
}
document.querySelectorAll('*').filter(el => {
return isEmpty(el);
});
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问题2:这个逻辑是否也会遍历所有孩子?
问题3:能否仅对块级元素使用此querySelector?