相关疑难解决方法(0)

如果类T包含对ILogger的依赖,则解析依赖关系:

public class Foo
{
    private ILogger _logger;

    public Foo(ILogger<Foo> logger)
    {
        _logger = logger;
    }
}

但以下不起作用,因为logger将为null:

public class Foo
{
    private ILogger _logger;

    public Foo(ILogger logger)
    {
        _logger = logger;
    }
}