相关疑难解决方法(0)

org.xml.sax.SAXParseException:prolog中不允许使用内容

我有一个基于Java的Web服务客户端连接到Java Web服务(在Axis1框架上实现).

我在日志文件中遇到以下异常:

Caused by: org.xml.sax.SAXParseException: Content is not allowed in prolog.
    at org.apache.xerces.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source)
    at org.apache.xerces.util.ErrorHandlerWrapper.fatalError(Unknown Source)
    at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)
    at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)
    at org.apache.xerces.impl.XMLScanner.reportFatalError(Unknown Source)
    at org.apache.xerces.impl.XMLDocumentScannerImpl$PrologDispatcher.dispatch(Unknown Source)
    at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source)
    at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
    at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
    at org.apache.xerces.parsers.XMLParser.parse(Unknown Source)
    at org.apache.xerces.parsers.AbstractSAXParser.parse(Unknown Source)
    at javax.xml.parsers.SAXParser.parse(Unknown Source)
    at org.apache.axis.encoding.DeserializationContext.parse(DeserializationContext.java:227)
    at org.apache.axis.SOAPPart.getAsSOAPEnvelope(SOAPPart.java:696)
    at org.apache.axis.Message.getSOAPEnvelope(Message.java:435)
    at org.apache.ws.axis.security.WSDoAllReceiver.invoke(WSDoAllReceiver.java:114)
    at org.apache.axis.strategies.InvocationStrategy.visit(InvocationStrategy.java:32)
    at org.apache.axis.SimpleChain.doVisiting(SimpleChain.java:118)
    at org.apache.axis.SimpleChain.invoke(SimpleChain.java:83)
    at org.apache.axis.client.AxisClient.invoke(AxisClient.java:198)
    at org.apache.axis.client.Call.invokeEngine(Call.java:2784)
    at org.apache.axis.client.Call.invoke(Call.java:2767)
    at org.apache.axis.client.Call.invoke(Call.java:2443)
    at org.apache.axis.client.Call.invoke(Call.java:2366)
    at org.apache.axis.client.Call.invoke(Call.java:1812)
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java xml

149
推荐指数
8
解决办法
52万
查看次数

Intellij IDEA崩溃,现在抛出一个错误

我在Intellij IDEA工作,但我的计算机冻结,所以我关闭了我的电脑.(长按电源按钮)当我打开电脑并启动IntelliJ IDEA时出现此错误:

Cannot load settings from file 'C:\Users\user\.IdeaIC13\config\options\code.style.schemes.xml': java.lang.AssertionError: Unexpected content storage modification File content will be recreated
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我关闭IDEA并重新开始,现在我没有上一个错误,但是当我打开我的项目时,我有这个错误:

Error:Internal error: (org.jdom.input.JDOMParseException) Error on line 1: Content is not allowed in prolog.
org.jdom.input.JDOMParseException: Error on line 1: Content is not allowed in prolog.
    at org.jdom.input.SAXBuilder.build(SAXBuilder.java:533)
    at org.jdom.input.SAXBuilder.build(SAXBuilder.java:946)
    at com.intellij.openapi.util.JDOMUtil.loadDocument(JDOMUtil.java:364)
    at com.intellij.openapi.util.JDOMUtil.loadDocument(JDOMUtil.java:342)
    at org.jetbrains.jps.model.serialization.JpsLoaderBase.loadRootElement(JpsLoaderBase.java:69)
    at org.jetbrains.jps.model.serialization.JpsLoaderBase.loadRootElement(JpsLoaderBase.java:40)
    at org.jetbrains.jps.model.serialization.JpsLoaderBase.loadComponents(JpsLoaderBase.java:52)
    at org.jetbrains.jps.model.serialization.JpsProjectLoader.loadFromDirectory(JpsProjectLoader.java:119)
    at org.jetbrains.jps.model.serialization.JpsProjectLoader.loadProject(JpsProjectLoader.java:98)
    at org.jetbrains.jps.model.serialization.impl.JpsSerializationManagerImpl.loadModel(JpsSerializationManagerImpl.java:41)
    at org.jetbrains.jps.cmdline.JpsModelLoaderImpl.loadModel(JpsModelLoaderImpl.java:45)
    at org.jetbrains.jps.cmdline.BuildRunner.load(BuildRunner.java:71)
    at org.jetbrains.jps.cmdline.BuildSession.runBuild(BuildSession.java:198)
    at org.jetbrains.jps.cmdline.BuildSession.run(BuildSession.java:113)
    at org.jetbrains.jps.cmdline.BuildMain$MyMessageHandler$1.run(BuildMain.java:133)
    at org.jetbrains.jps.service.impl.SharedThreadPoolImpl$1.run(SharedThreadPoolImpl.java:41)
    at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:511)
    at java.util.concurrent.FutureTask.run(FutureTask.java:266) …
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java android intellij-idea

99
推荐指数
4
解决办法
6万
查看次数

Java解析XML文档给出了"prolog中不允许的内容".错误

我正在用Java编写一个程序,它接受一个自定义XML文件并解析它.我正在使用XML文件进行存储.我在Eclipse中收到以下错误.

[Fatal Error] :1:1: Content is not allowed in prolog.
org.xml.sax.SAXParseException: Content is not allowed in prolog.
    at com.sun.org.apache.xerces.internal.parsers.DOMParser.parse(DOMParser.java:239)
    at     com.sun.org.apache.xerces.internal.jaxp.DocumentBuilderImpl.parse(DocumentBuilderImpl.java:283  )
    at javax.xml.parsers.DocumentBuilder.parse(DocumentBuilder.java:208)
    at me.ericso.psusoc.RequirementSatisfier.parseXML(RequirementSatisfier.java:61)
    at me.ericso.psusoc.RequirementSatisfier.getCourses(RequirementSatisfier.java:35)
    at     me.ericso.psusoc.programs.RequirementSatisfierProgram.main(RequirementSatisfierProgram.java:23  )
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包含XML文件的开头:

<?xml version="1.0" ?>
<PSU>
     <Major id="IST">
        <name>Information Science and Technology</name>
        <degree>B.S.</degree>
        <option> Information Systems: Design and Development Option</option>
        <requirements>
            <firstlevel type="General_Education" credits="45">
                <component type="Writing_Speaking">GWS</component>
                <component type="Quantification">GQ</component>
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该程序能够读取XML文件,但是当我调用DocumentBuilder.parse(XMLFile)解析时org.w3c.dom.Document,我得到上面的错误.

在我看来,我的XML文件的prolog中包含无效内容.我无法弄清楚出了什么问题.请帮忙.谢谢.

java xml eclipse xml-parsing

49
推荐指数
4
解决办法
29万
查看次数

SAXParseException:prolog中不允许使用内容

我需要将以下文件添加到我的Tomcat的'/ conf'目录中:

<?xml version="1.0" encoding="UTF-8"?>
<Context useHttpOnly="false" path="/bbc">
    <Realm className="com.bbc.tomcat.BBCSecurityRealm"/>
</Context>
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添加此文件后,Tomcat启动时出现以下错误"

ERROR ecmdefault util.digester.Digester 18:37:14,477 localhost-startStop-1 : Parse Fatal Error at line 1 column 1: Content is not allowed in prolog.
org.xml.sax.SAXParseException: Content is not allowed in prolog.
    at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(ErrorHandlerWrapper.java:195)
    at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.fatalError(ErrorHandlerWrapper.java:174)
    at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(XMLErrorReporter.java:388)
    at com.sun.org.apache.xerces.internal.impl.XMLScanner.reportFatalError(XMLScanner.java:1427)
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java tomcat sax

7
推荐指数
1
解决办法
6万
查看次数

“内容不允许在序言中”错误但在 XML 声明之前没有任何内容

首先我已经彻底检查了以下问题,这个问题似乎不是一回事:

这些似乎都归结为两件事:

  1. 开场前有一个或多个(可能不可见)字符 <?xml?>标签。
  2. 正文中有一些字节序列encoding<?xml?>标签中定义的不符。

至于#1,我用 来检查我的文件xxd,结果显示在此处:

$ xxd sample.fo
00000000: 3c3f 786d 6c20 7665 7273 696f 6e3d 2231  <?xml version="1
00000010: 2e30 2220 656e 636f 6469 6e67 3d22 5554  .0" encoding="UT
00000020: 462d 3822 3f3e 5465 7374 206d 6174 6572  F-8"?>Test mater
00000030: 6961 6c20 6963 6f6e 7354 6869 7320 746f  ial iconsThis to
00000040: 7069 6320 7465 7374 7320 7468 6520 …
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xml saxon xml-parsing apache-fop

5
推荐指数
1
解决办法
2万
查看次数

java - SAXparserException:prolog中不允许使用内容

我在尝试解析XML文档时遇到异常.

我在这里这里经历过很多帖子.但我的问题仍未解决.我检查了我在标题中也没有任何空格.我用记事本创建了它,我在保存时选择编码为utf-8.

我的XML文件看起来像这样

<?xml version="1.0" encoding="UTF-8"?>
<poem>
<title>Roses are Red</title>
<l>Roses are red</l>
</poem>
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我正在使用java加载文件并解析它.我的java代码是

File xml = new File("d:\\uploads\test.xml");
try{  
     XMLReader xr = XMLReaderFactory.createXMLReader();
     MySAXApp handler = new MySAXApp();
     xr.setContentHandler(handler);
     xr.setErrorHandler(handler);
     FileReader r = new FileReader(xml);
     xr.parse(new InputSource(r));
 }
 catch(Exception e)
 {
      log.info("Exception : "+e.getMessage());
 }
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我的MySAXApp课程如下

package utility;
import java.io.FileReader;
import java.util.logging.Logger;
import org.xml.sax.XMLReader;
import org.xml.sax.Attributes;
import org.xml.sax.InputSource;
import org.xml.sax.helpers.XMLReaderFactory;
import org.xml.sax.helpers.DefaultHandler;

public class MySAXApp extends DefaultHandler {

    public Logger log;
    public MySAXApp () …
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java xml sax saxparser

-2
推荐指数
1
解决办法
8791
查看次数