相关疑难解决方法(0)

我有这个代码来自django示例教程

from django.db import models
from datetime import datetime

# Create your models here.

class Poll(models.Model):
    question = models.CharField(max_length=200)
    pub_date = models.DateTimeField('date published')

    def __unicode__(self):
        return self.question

    def was_published_today(self):
        return self.pub_date.date() == datetime.date.today()  

我收到此错误:IndentationError:意外缩进

在这条线上:

def __unicode__(self):

任何想法有什么不对？

我在下面编写了这个脚本,它将数字转换成它的拼写.

no = raw_input("Enter a number: ")

strcheck = str(no)
try:
     val = int(no)
except ValueError:
     print("sayi degil")
     raise SystemExit
lencheck = str(no)
if len(lencheck) > 6:
     print("Bu sayi cok buyuk !")
     raise SystemExit

n = int(no)
print(n)
def int2word(n):

     n3 = []
     r1 = ""

     ns = str(n)
     for k in range(3, 33, 3):
              r = ns[-k:]
              q = len(ns) - k

    if q < -2:
        break
    else:
        if  q >= 0:
            n3.append(int(r[:3]))
        elif q >= -1:
            n3.append(int(r[:2]))
        elif …

我已经尝试过notepad ++和eclipse但是即便如此,它在第18行显示了一个缩进错误.我不知道,为什么它会给我一个像这样的错误......？请帮我.

from brisa.core.reactors.qtreactor import QtReactor
reactor = QtReactor()
from brisa.core import config
from brisa.upnp.device import Device
from brisa.upnp.device.service import Service, StateVariable
class QtDevice(QtGui.QWidget):
     def __init__(self):

         QtGui.QWidget.__init__(self)
         self.verticalLayout = QtGui.QVBoxLayout(self)
         self.title = QtGui.QLabel("Qt Simple Device")
         font = QtGui.QFont()
         font.setPointSize(15)
         self.title.setFont(font)
         self.title.setAlignment(QtCore.Qt.AlignCenter)
         self.verticalLayout.addWidget(self.title)
         self.lineEdit = QtGui.QLineEdit(self)
         self.verticalLayout.addWidget(self.lineEdit)
         self.search_btn = QtGui.QPushButton("Start Device", self)
         self.verticalLayout.addWidget(self.search_btn)
         QtCore.QObject.connect(self.search_btn, QtCore.SIGNAL("clicked()"), self.start)
         self.stop_btn = QtGui.QPushButton("Stop Device", self)
         self.verticalLayout.addWidget(self.stop_btn)
         QtCore.QObject.connect(self.stop_btn, QtCore.SIGNAL("clicked()"), self.stop)
         self.lineEdit.setText(’My Generic Device Name’)
         self.root_device = None
         self.upnp_urn = ’urn:schemas-upnp-org:device:MyDevice:1’


     def _add_root_device(self):
         project_page = ’http://brisa.garage.maemo.org’
         serial_no …

我的缩进有什么问题？

>>> try:
        print("Hello World!")
    except:

  File "<pyshell#2>", line 3
    except:
          ^
IndentationError: unindent does not match any outer indentation level

使用IDLE Python 2.7.2,Shell; 在try语句之后,我尝试退格到正确的缩进,但它转到左边距,我必须键入4个空格.

list=['a','a','x','c','e','e','f','f','f']

i=0
count = 0

while count < len(list)-2:
    if list[i] == list[i+1]:
        if list [i+1] != list [i+2]:
            print list[i]
            i+=1
            count +=1
        else:print "no"
    else:   
        i +=1
        count += 1

我越来越:

    else:print "no"
   ^
 IndentationError: unexpected indent

我试图只打印匹配以下元素的elts,但不打印后面的元素.我是Python的新手,我不确定为什么这不起作用.

我正在尝试解析XML文档并获取某些标记.我想获取名称标签(仅当它是嵌套在艺术家中的名称标签)和标题标签(仅当它是嵌套在发布中的标签).
这不是太重要,但重要的是,我出于某种原因得到一个错误,说elif语句是无效的语法
我已查看其他帖子并确保我的标签是正确的,并且没有任何任何if之后的额外换行符.

这是代码片段:

from lxml import etree
import sys

#infile = raw_input("Please enter an XML file to parse:  ")
outfile = open('results.txt', 'a')

path = []
for event, elem in etree.iterparse('releases7.xml', events=("start", "end")):
    if event == 'start':
        path.append(elem.tag)
    elif event == 'end':
        # process the tag
        if elem.tag == 'name':
            if 'artist' in path and not 'extraartists' in path and not 'track' in path:
                outfile.write( 'artist = ' + elem.text.encode('utf-8') + '\n' )
        elif elem.tag == 'title':
            if 'release' …

鉴于以下解释器会话:

>>> def func(depth,width):
...   if (depth!=0):
...     for i in range(width):
...       print(depth,i)
...       func(depth-1,width)
  File "<stdin>", line 5
    func(depth-1,width)
                  ^
TabError: inconsistent use of tabs and spaces in indentation

有人可以告诉我TabError我的代码是什么？

我正在使用Python 2.7并编写了以下内容：

def算术（A）：
    x = 1
“”
一些评论在这里
“”  
    如果x = 1：
        x = 1
    elif x = 2：
        x = 2
    返回0

但是它有缩进的问题：

    如果x = 1：
    ^
IndentationError：意外缩进

那么如何在函数中写注释呢？

我在解释器提示符下尝试了这段代码：

>>> x = 7
>>> if x > 5:
... print("five")

我收到此错误消息：

File "<stdin>", line 2
    print("five") 
IndentationError: expected an indented block

为什么？

我的IndentationError看起来似乎无法解决. http://pastebin.com/AFdnYcRc.

#!/usr/bin/env python
import os
import glob
import shutil
import mutagen
from sys import exit

musicdir = raw_input("What directory are the music files located in? : ")
musfile = glob.glob(musicdir + '/' + "*.mp3")
musfile1 = glob.glob(musicdir + '/' + "*.flac")
musfile.extend(musfile1)
newmusicdir = raw_input("What directory should the music files be organized into? : ")


done = False

while not done:
    for m in musfile:
        if musfile:
            try:
                musta = mutagen.File(m, easy=True)
                mar = str(musta['artist'][0])
                mal = str(musta['album'][0]) …