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给定lat/long中的现有点,(以KM表示)和方位(以度数转换为弧度)的距离,我想计算新的纬度/经度.这个网站反复出现,但我无法让这个公式为我工作.

采用上述链接的公式为:

lat2 = asin(sin(lat1)*cos(d/R) + cos(lat1)*sin(d/R)*cos(?))

lon2 = lon1 + atan2(sin(?)*sin(d/R)*cos(lat1), cos(d/R)?sin(lat1)*sin(lat2))

上述公式适用于MSExcel,其中 -

asin          = arc sin()   
d             = distance (in any unit)   
R             = Radius of the earth (in the same unit as above)  
and hence d/r = is the angular distance (in radians)  
atan2(a,b)    = arc tan(b/a)  
? is the bearing (in radians, clockwise from north);  

这是我在Python中获得的代码.

import math

R = 6378.1 #Radius of the Earth
brng = 1.57 #Bearing is 90 degrees converted …

我正在使用以下函数从种子点生成指定半径内的随机地理坐标:

function randomGeo(center, radius) {
    var y0 = center.latitude;
    var x0 = center.longitude;
    var rd = radius / 111300;

    var u = Math.random();
    var v = Math.random();

    var w = rd * Math.sqrt(u);
    var t = 2 * Math.PI * v;
    var x = w * Math.cos(t);
    var y = w * Math.sin(t);

    var xp = x / Math.cos(y0);

    return {
        'latitude': y + y0,
        'longitude': xp + x0
    };
}

我使用2000米半径和以下种子点在循环中多次执行此操作:

location: { // Oxford
    latitude: 51.73213,
    longitude: -1.20631 …