相关疑难解决方法(0)

无法通过不合逻辑的线pep8错误

我一直试图解决这个问题一段时间,我不能让它通过pep8.这是我的代码:

1.

if (len(regex) > 2 and regex[0] == '(' and regex[-1] == ')' and 
    sum(regex.count(char) for char in splitter) == 1 and 
    regex.count('(') == 1 and regex.count(')') == 1):

    print('hi')
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2.

if (len(regex) > 2 and regex[0] == '(' and regex[-1] == ')' and 
    sum(regex.count(char) for char in splitter) == 1 and 
    regex.count('(') == 1 and regex.count(')') == 1):

    print('hi')
Run Code Online (Sandbox Code Playgroud)

3.

if (len(regex) > 2 and regex[0] == '(' and regex[-1] == ')' 
    and regex.count('(') > 1):

    print('hi')
Run Code Online (Sandbox Code Playgroud)

我在3个if语句中得到以下PEP8错误: …

python if-statement pep8

8
推荐指数
1
解决办法
4947
查看次数

标签 统计

if-statement ×1

pep8 ×1

python ×1