相关疑难解决方法(0)

我正在使用Spring MVC和Jackson进行JSON de /序列化.但我面临序列化日期的问题.

默认情况下,杰克逊将日期序列化为时代.但我想将其序列化为ISO日期(即06-10-2011 11:00:00).

下面的代码是我的spring配置,但它不起作用.它仍然返回一个纪元日期.

所以我的问题是,如何序列化为非纪元日期？

<!-- JSON -->
<bean id="jsonConverter" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter">
    <property name="supportedMediaTypes" value="application/json" />
    <property name="objectMapper" ref="jacksonObjectMapper" />
</bean>

<bean id="jacksonObjectMapper" class="org.codehaus.jackson.map.ObjectMapper" />

<bean id="jacksonSerializationConfig" class="org.codehaus.jackson.map.SerializationConfig" factory-bean="jacksonObjectMapper" factory-method="getSerializationConfig" />

<bean class="org.springframework.beans.factory.config.MethodInvokingFactoryBean">
    <property name="targetObject" ref="jacksonSerializationConfig" />
    <property name="targetMethod" value="setSerializationInclusion" />
    <property name="arguments">
        <list>
            <value type="org.codehaus.jackson.map.annotate.JsonSerialize.Inclusion">NON_NULL</value>
        </list>
    </property>
</bean>

<bean class="org.springframework.beans.factory.config.MethodInvokingFactoryBean">
    <property name="targetObject" ref="jacksonSerializationConfig" />
    <property name="targetMethod" value="setDateFormat" />
    <property name="arguments">
        <list>
            <value type="java.text.SimpleDateFormat">yyyy-MM-dd'T'HH:mm:ss.SSSZ</value>
        </list>
    </property>
</bean>

<bean class="org.springframework.beans.factory.config.MethodInvokingFactoryBean">
    <property name="targetObject" ref="jacksonSerializationConfig" />
    <property name="targetMethod" value="enable" />
    <property …