相关疑难解决方法(0)

如果我有一个功能,int *&它意味着什么？如何只将int或指针int传递给该函数？

function(int *& mynumber);

每当我尝试将指针传递给该函数时,它会说:

error: no matching function for call to 'function(int *)'
note: candidate is 'function(int *&)'

在以下代码中:

void insert(Node *& aNode, int x) {
  if (!aNode) {
    aNode = new Node(x);
    aNode->next = aNode;
    return;
  }

  Node *p = aNode;
  Node *prev = NULL;
  do {
    prev = p;
    p = p->next;
    if (x <= p->data && x >= prev->data) break;   // For case 1)
    if ((prev->data > p->data) && (x < p->data || x > prev->data)) break; // For case 2)
  } while (p != aNode);   // when back to starting point, then stop. For …