相关疑难解决方法(0)

有没有一种方法可以使以下工作无需在子类中定义一个实现，它只是调用超类或不必要地重复非专用签名？

class Emitter {
    on(name: 'one', handler: (value: number) => void): void;
    on(name: string, handler: (...args: any[]) => void): void;
    on(name: string, handler: (...args: any[]) => void): void { 
        // do stuff
    }
}


class Subclass extends Emitter {
    on(name: 'two', handler: (value: string) => void): void;
    on(name: string, handler: (...args: any[]) => void): void;
    // error no implementation specified
}


interface IEmitter {
    on(name: 'one', handler: (value: number) => void): void;
    on(name: string, handler: (...args: any[]) => void): void; …

我目前正在尝试改进现有代码的类型.我的代码看起来大致如下:

/* dispatcher.ts */
interface Message {
    messageType: string;
}

class Dispatcher<M extends Message> {    
    on<
        MessageType extends M["messageType"],
        SubMessage extends M & { messageType: MessageType }
    >(
        messageType: MessageType,
        handler: (message: SubMessage) => void
    ): void { }
}

/* messages.ts */
interface AddCommentMessage {
    messageType: "ADD_COMMENT";
    commentId: number;
    comment: string;
    userId: number;
}

interface PostPictureMessage {
    messageType: "POST_PICTURE";
    pictureId: number;
    userId: number;
}

type AppMessage = AddCommentMessage | PostPictureMessage;

/* app.ts */
const dispatcher = new Dispatcher<AppMessage>();

dispatcher.on("ADD_COMMENT", …