相关疑难解决方法(0)

我有这个代码:

RijndaelManaged rijndaelCipher = new RijndaelManaged();

            // Set key and IV
            rijndaelCipher.Key = Convert.FromBase64String("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz012345678912");
            rijndaelCipher.IV = Convert.FromBase64String("1234567890123456789012345678901234567890123456789012345678901234");

我被抛出:

Specified key is not a valid size for this algorithm.

Specified initialization vector (IV) does not match the block size for this algorithm.

这个字符串出了什么问题？我能算一下你的一些例子吗？

对c#来说很新,目前在解密长密码时遇到问题,错误是

指定的密钥不是此算法的有效大小

我知道这与加密密码位长度不受支持有关,但不确定如何建议允许这些更长密码的方法.

这是我的加密和解密

"cipherKey":"0123456789abcdef","cipherVector":"somereallycooliv"

using System;
using System.Security.Cryptography;
using System.IO;
using System.Text;

namespace DataApi
{
public class Encryption
{
    private readonly IConfigurationService _configService;


    private const string _vector = "cipherVector";
    private const string _key = "cipherKey";

    public Encryption(IConfigurationService configService)
    {
        _configService = configService;
    }
    public string EncryptString(string text)
    {
        if(string.IsNullOrEmpty(text))
        {
            return "";
        }
        try
        {

      var key = Encoding.UTF8.GetBytes(_configService.Get(_key));
        byte[] IV = Encoding.ASCII.GetBytes(_configService.Get(_vector));

        using (var aesAlg = Aes.Create())
        {
            using (var encryptor = aesAlg.CreateEncryptor(key, IV))
            {
                using (var msEncrypt …