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如何在路线google maps v2 android上绘制交互式Polyline

我有以下代码为我绘制折线并且工作正常,但问题是它没有绘制交互式折线,绘制的线条缺少一些像素!

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
import java.util.ArrayList;
import java.util.List;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONArray;
import org.json.JSONObject;

import com.google.android.gms.maps.CameraUpdateFactory;
import com.google.android.gms.maps.GoogleMap;
import com.google.android.gms.maps.SupportMapFragment;
import com.google.android.gms.maps.model.BitmapDescriptorFactory;
import com.google.android.gms.maps.model.LatLng;
import com.google.android.gms.maps.model.MarkerOptions;
import com.google.android.gms.maps.model.Polyline;
import com.google.android.gms.maps.model.PolylineOptions;

import android.app.ProgressDialog;
import android.content.Context;
import android.graphics.Color;
import android.os.AsyncTask;
import android.os.Bundle;
import android.support.v4.app.FragmentActivity;
import android.util.Log;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;

public class testRoute extends FragmentActivity implements OnClickListener {

    private GoogleMap myMap;
    Polyline line; …
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android google-maps google-maps-android-api-2

50
推荐指数
4
解决办法
11万
查看次数

使用新的Google Maps API解码折线

我正在绘制地图中两点之间的路线.我这样得到了积分:

StringBuilder urlString = new StringBuilder();
    urlString.append("http://maps.googleapis.com/maps/api/directions/json");
    urlString.append("?origin=");// from
    urlString.append(Double.toString(src.latitude));
    urlString.append(",");
    urlString.append(Double.toString(src.longitude));
    urlString.append("&destination=");// to
    urlString.append(Double.toString(dest.latitude));
    urlString.append(",");
    urlString.append(Double.toString(dest.longitude));
    urlString.append("&sensor=false&mode=");
    if (tipo != null) {
        urlString.append(tipo);
    }
return urlString.toString;
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我收到了Google的回复,并获得了JSON:

resp = new JSONObject(builder.toString());
                Log.i("Location", "Contenido del kml: "+resp);
                JSONArray routeObject = resp.getJSONArray("routes");
                JSONObject routes = routeObject.getJSONObject(0);
                JSONObject overviewPolylines = routes
                        .getJSONObject("overview_polyline");
                String encodedString = overviewPolylines.getString("points");
                ArrayList<LatLng> puntos=decodePoly(encodedString);
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我从谷歌获得的回复:(采用JSON格式):

Response: {"status":"OK","routes":[{"waypoint_order":[],"summary":"R-3 and A-3","bounds":{"southwest":{"lng":-3.676540000000001,"lat":40.00040000000001},"northeast":{"lng":-2.99933,"lat":40.43357}},"legs":[{"duration":{"value":3267,"text":"54 mins"},"distance":{"value":85039,"text":"85.0 km"},"end_location":{"lng":-2.99933,"lat":40.00040000000001},"start_address":"Calle del General Díaz Porlier, 91, 28006 Madrid, Spain","end_address":"Camino Veinticuatro, 2, 16400 Tarancón, Cuenca, Spain","start_location":{"lng":-3.676540000000001,"lat":40.43331000000001},"via_waypoint":[],"steps":[{"html_instructions":"Head <b>north<\/b> on <b>Calle …
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android google-maps polyline

22
推荐指数
3
解决办法
3万
查看次数