我正在尝试运行,pip install mysql-python connector但它一直给我一个错误" 无法打开包含文件:'config-win.h' ".
安装在我的Mac和另一台Windows机器上运行正常,但不是这个.我已经下载了Visual Studio C++并尝试安装32位和64位.
_mysql.c(42) : fatal error C1083: Cannot open include file: 'config-win.h': No s
uch file or directory
error: command 'C:\\Program Files (x86)\\Microsoft Visual Studio 9.0\\VC\\BIN\\c
l.exe' failed with exit status 2
----------------------------------------
Cleaning up...
Command C:\Users\Admin1\Desktop\python\virtual\Scripts\python.exe -c "import set
uptools, tokenize;__file__='C:\\Users\\Admin1\\Desktop\\python\\virtual\\build\\
MySQL-python\\setup.py';exec(compile(getattr(tokenize, 'open', open)(__file__).r
ead().replace('\r\n', '\n'), __file__, 'exec'))" install --record c:\users\admin
1\appdata\local\temp\1\pip-6pmwrd-record\install-record.txt --single-version-ext
ernally-managed --compile --install-headers C:\Users\Admin1\Desktop\python\virtu
al\include\site\python2.7 failed with error code 1 in C:\Users\Admin1\Desktop\py
thon\virtual\build\MySQL-python
Storing debug log for …Run Code Online (Sandbox Code Playgroud) 我需要使用sqlalchemy在mysql中创建一个db,如果它已经存在,我可以连接到db,但是我希望能够创建它,如果它不存在的话.这是我的表:
#def __init__(self):
Base = declarative_base()
class utente(Base):
__tablename__="utente"
utente_id=Column(Integer,primary_key=True)
nome_utente=Column(Unicode(20))
ruolo=Column(String(10))
MetaData.create_all()
def __repr(self):
return "utente: {0}, {1}, id: {2}".format(self.ruolo,self.nome_utente,self.utente_id)
class dbmmas(Base):
__tablename__="dbmmas"
db_id=Column(Integer,primary_key=True,autoincrement=True)
nome_db=Column(String(10))
censimento=Column(Integer)
versione=Column(Integer)
ins_data=Column(DateTime)
mod_data=Column(DateTime)
ins_utente=Column(Integer)
mod_utente=Column(Integer)
MetaData.create_all()
def __repr(self):
return "dbmmas: {0}, censimento {1}, versione {2}".format(self.nome_db,self.censimento,self.versione)
class funzione(Base):
__tablename__="funzione"
funzione_id=Column(Integer,primary_key=True,autoincrement=True)
categoria=Column(String(10))
nome=Column(String(20))
def __repr__(self):
return "funzione:{0},categoria:{1},id:{2} ".format(self.nome,self.categoria,self.funzione_id)
class profilo(Base):
__tablename__="rel_utente_funzione"
utente_id=Column(Integer,primary_key=True)
funzione_id=Column(Integer,primary_key=True)
amministratore=Column(Integer)
MetaData.create_all()
def __repr(self):
l=lambda x: "amministratore" if x==1 else "generico"
return "profilo per utente_id:{0}, tipo: {1}, funzione_id: {2}".format(self.utente_id,l(self.amministratore),self.funzione_id)
class aree(Base):
__tablename__="rel_utente_zona" …Run Code Online (Sandbox Code Playgroud) 我试图读取一个由数百万行组成的非常大的 MySQL 表。我使用过Pandas库和chunks. 请参阅下面的代码:
import pandas as pd
import numpy as np
import pymysql.cursors
connection = pymysql.connect(user='xxx', password='xxx', database='xxx', host='xxx')
try:
with connection.cursor() as cursor:
query = "SELECT * FROM example_table;"
chunks=[]
for chunk in pd.read_sql(query, connection, chunksize = 1000):
chunks.append(chunk)
#print(len(chunks))
result = pd.concat(chunks, ignore_index=True)
#print(type(result))
#print(result)
finally:
print("Done!")
connection.close()
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实际上,如果我限制要选择的行数,执行时间是可以接受的。但是如果只想选择最少的数据(例如100 万行),那么执行时间会急剧增加。
也许有更好/更快的方法从python中的关系数据库中选择数据?
我尝试使用 docker 连接 Mysql 与 django,但出现此错误
2061, 'RSA Encryption not supported - caching_sha2_password plugin was built with GnuTLS support'.
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我尝试更改用户并创建数据库
// create a user //
CREATE USER 'user'@'localhost' IDENTIFIED BY 'user';
GRANT ALL PRIVILEGES ON *.* TO 'user'@'localhost' WITH GRANT OPTION;
CREATE USER 'user'@'%' IDENTIFIED BY 'user';
GRANT ALL PRIVILEGES ON *.* TO 'user'@'%' WITH GRANT OPTION;
// create a database //
CREATE DATABASE user_db;
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但仍然是 sqme 错误消息
在设置.py
DATABASES = {
'default': {
'ENGINE': 'django.db.backends.mysql',
'NAME': 'user_db',
'USER': 'user', …Run Code Online (Sandbox Code Playgroud)