我想把头发拉出来; 这是超级简单的,我有脑冻结或它不是那么简单.

我想要的是

当用户访问时,我试图使用firebase取消缩短缩短的URL:所以
myapp.firebaseappurl.com/url/SHORTENEDLINK
我不会让我添加缩短的URL

我希望输出为:

{
  "url": "https://stackoverflow.com/questions/45420989/sphinx-search-how-to-use-an-empty-before-match-and-after-match"
}

我试过了什么

firebase.json 文件:

{
  "hosting": {
    "public": "public",
    "rewrites": [ {
    "source": "/url/:item",
      "destination": "/url/:item"
    } ]
  }
}

index.js 文件:

const functions = require('firebase-functions');

exports.url = functions.https.onRequest((requested, response) => {

    var uri = requested.url;
    request({
        uri: uri,
        followRedirect: true
      },
      function(err, httpResponse) {
        if (err) {
          return console.error(err);
        }
        response.send(httpResponse.headers.location || uri);
      }
    );

});

结果

当我去的时候,myapp.firebaseappurl.com/url/SHORTENEDLINK我得到以下内容:

Error: could not handle the request