相关疑难解决方法(0)

这是我的清单

    <service android:name=".fcm.PshycoFirebaseMessagingServices">
        <intent-filter>
            <action android:name="com.google.firebase.MESSAGING_EVENT" />
        </intent-filter>
    </service>

    <service android:name=".fcm.PshycoFirebaseInstanceIDService">
        <intent-filter>
            <action android:name="com.google.firebase.INSTANCE_ID_EVENT" />
        </intent-filter>
    </service>

当应用程序处于后台并且通知到达时,默认通知将会运行并且不会运行我的代码onMessageReceived.

这是我的onMessageReceived代码.如果我的应用程序在前台运行,而不是在后台应用程序时,则调用此方法.如何在应用程序处于后台时运行此代码？

// [START receive_message]
@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
    // TODO(developer): Handle FCM messages here.
    // If the application is in the foreground handle both data and notification messages here.
    // Also if you intend on generating your own notifications as a result of a received FCM
    // message, here is where that should be initiated. See …

我正在使用Firebase,并在应用程序处于后台时测试从我的服务器向我的应用发送通知.通知成功发送,甚至出现在设备的通知中心,但是当通知出现或甚至我点击它时,我的FCMessagingService内的onMessageReceived方法永远不会被调用.

当我在我的应用程序位于前台时对此进行测试时,调用了onMessageReceived方法,一切正常.当应用程序在后台运行时会出现此问题.

这是预期的行为,还是有办法解决这个问题？

这是我的FBMessagingService:

import android.util.Log;

import com.google.firebase.messaging.FirebaseMessagingService;
import com.google.firebase.messaging.RemoteMessage;

public class FBMessagingService extends FirebaseMessagingService {

    @Override
    public void onMessageReceived(RemoteMessage remoteMessage) {
        Log.i("PVL", "MESSAGE RECEIVED!!");
        if (remoteMessage.getNotification().getBody() != null) {
            Log.i("PVL", "RECEIVED MESSAGE: " + remoteMessage.getNotification().getBody());
        } else {
            Log.i("PVL", "RECEIVED MESSAGE: " + remoteMessage.getData().get("message"));
        }
    }
}