相关疑难解决方法(0)

我没有成功浏览网页以获得以下简单问题的解决方案:

如何使用顶点值绘制3D多边形(比如填充的矩形或三角形)？我尝试过很多想法,但都失败了,请看:

from mpl_toolkits.mplot3d import Axes3D
from matplotlib.collections import PolyCollection
import matplotlib.pyplot as plt
fig = plt.figure()
ax = Axes3D(fig)
x = [0,1,1,0]
y = [0,0,1,1]
z = [0,1,0,1]
verts = [zip(x, y,z)]
ax.add_collection3d(PolyCollection(verts),zs=z)
plt.show()

我提前感谢任何想法/评论.

根据接受的答案更新:

import mpl_toolkits.mplot3d as a3
import matplotlib.colors as colors
import pylab as pl
import scipy as sp

ax = a3.Axes3D(pl.figure())
for i in range(10000):
    vtx = sp.rand(3,3)
    tri = a3.art3d.Poly3DCollection([vtx])
    tri.set_color(colors.rgb2hex(sp.rand(3)))
    tri.set_edgecolor('k')
    ax.add_collection3d(tri)
pl.show()

结果如下:

我正在尝试绘制几个(数千个)圆形对象 - 我没有太多使用python的经验.我有兴趣指定位置,半径和颜色.有没有更有效的方法来实现相同的结果？:

import matplotlib.pyplot as plt

xvals = [0,.1,.2,.3]
yvals = [0,.1,.2,.3]
rvals = [0,.1,.1,.1]

c1vals = [0,.1,0..1]
c2vals = [.1,0,.1,0]
c3vals = [.1,.1,.1,.1]

for q in range(0,4):
    circle1=plt.Circle((xvals[q], yvals[q]), rvals[q], color=[0,0,0])
    plt.gcf().gca().add_artist(circle1)