相关疑难解决方法(0)

我想知道是否有一条快捷方式可以在Python列表中列出一个简单的列表.

我可以在for循环中做到这一点,但也许有一些很酷的"单行"？我用reduce尝试了,但是我收到了一个错误.

码

l = [[1, 2, 3], [4, 5, 6], [7], [8, 9]]
reduce(lambda x, y: x.extend(y), l)

错误信息

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 1, in <lambda>
AttributeError: 'NoneType' object has no attribute 'extend'

因此stdin将文本的一行引回到列表中,并且多行文本都是列表元素.你怎么把它们分成单个单词？

mylist = ['this is a string of text \n', 'this is a different string of text \n', 'and for good measure here is another one \n']

想要输出:

newlist = ['this', 'is', 'a', 'string', 'of', 'text', 'this', 'is', 'a', 'different', 'string', 'of', 'text', 'and', 'for', 'good', 'measure', 'here', 'is', 'another', 'one']

我在下面有一个清单。我想拆分如下：

['动画'，'儿童'，'喜剧'，'冒险'，'儿童'，'奇幻'，'喜剧'，'浪漫'，'喜剧'，'戏剧']

clist = ["Animation|Children's|Comedy",

"Adventure|Children's|Fantasy",

'Comedy|Romance',

'Comedy|Drama']

 

for i,x in enumerate(clist):

    if '|' in x:

        clist[i] = x[:x.index('|')]

它返回这个：

['动画'、'冒险'、'喜剧'、'喜剧']

lst = [
  "Zambia",
  "Zimbabwe",
  "Suite,203,2880,Zanker,Rd,San,Jose,95134",
  "1496A,1st,and,2nd,Floor,19th,main,8th,crossSector,1,HSR,Layout,Bengaluru,560102",
]

在这里,我有一个世界.有些是实际的话只是一个示例("赞"),有些是喜欢的句子只是例子("组曲,203,2880,Zanker,路,三,圣何塞,95134")

我怎样才能将它们转换成以下格式.

lst = [
  "Zambia",
  "Zimbabwe",
  "Suite",
  "203",
  "2880",
  "Zanker",
  "Rd",
  "San",
  "Jose",
  "95134,
  "1496A",
  "1st",
  "and",
  "2nd",
  "Floor",
  "19th",
  "main",
  "8th",
  "crossSector",
  "1",
  "HSR",
  "Layout",
  "Bengaluru",
  "560102",
  "g2crowd_badge2",
  "Created with Sketch."
]

如何使用python将列表转换为此格式

请看看这个.