相关疑难解决方法(0)

如何恢复传递给multiprocessing.Process的函数的返回值?

在下面的示例代码中,我想恢复函数的返回值worker.我该怎么做呢?这个值存储在哪里?

示例代码:

import multiprocessing

def worker(procnum):
    '''worker function'''
    print str(procnum) + ' represent!'
    return procnum


if __name__ == '__main__':
    jobs = []
    for i in range(5):
        p = multiprocessing.Process(target=worker, args=(i,))
        jobs.append(p)
        p.start()

    for proc in jobs:
        proc.join()
    print jobs
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输出:

0 represent!
1 represent!
2 represent!
3 represent!
4 represent!
[<Process(Process-1, stopped)>, <Process(Process-2, stopped)>, <Process(Process-3, stopped)>, <Process(Process-4, stopped)>, <Process(Process-5, stopped)>]
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我似乎无法在存储的对象中找到相关属性jobs.

提前谢谢,blz

python python-multiprocessing

143
推荐指数
9
解决办法
14万
查看次数

在python多处理中修改对象

我有一大堆自定义对象,我需要执行独立(可并行化)的任务,包括修改对象参数.我尝试过使用Manager().dict和'sharedmem'ory,但两者都没有用.例如:

import numpy as np
import multiprocessing as mp
import sharedmem as shm


class Tester:

    num = 0.0
    name = 'none'
    def __init__(self,tnum=num, tname=name):
        self.num  = tnum
        self.name = tname

    def __str__(self):
        return '%f %s' % (self.num, self.name)

def mod(test, nn):
    test.num = np.random.randn()
    test.name = nn


if __name__ == '__main__':

    num = 10

    tests = np.empty(num, dtype=object)
    for it in range(num):
        tests[it] = Tester(tnum=it*1.0)

    sh_tests = shm.empty(num, dtype=object)
    for it in range(num):
        sh_tests[it] = tests[it]
        print sh_tests[it]

    print '\n' …
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python parallel-processing multiprocessing

14
推荐指数
2
解决办法
9954
查看次数