相关疑难解决方法(0)

我需要我的PHP应用程序才能创建一个SQLite表,但前提是它还不存在.我该怎么办呢？

我的代码包含一个数据库类.运行它时显示有关CREATE TABLE IF NOT EXISTS语句的错误.请给我解决方案来纠正错误.

clasdbOpenHelper.java

package example.events1;

import android.content.Context;
import android.database.Cursor;
import android.database.SQLException;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;


public class classdbOpenHelper extends SQLiteOpenHelper {

    public static final String KEY_ROWID = "_id";
    public static final String KEY_DESC = "countdesc";
    public static final String KEY_DATE = "countdate";
    public static final String KEY_EVENT = "countevent";
    public static final String DATABASE_NAME= "countdb";
    public static final String DATABASE_TABLE = "countable";
    public static final int DATABASE_VERSION = 1;


    public classdbOpenHelper(Context context) {
        super(context, DATABASE_NAME, null, DATABASE_VERSION); …