相关疑难解决方法(0)

在尝试评估Python中的定积分时,我收到以下错误代码.

AttributeError                            Traceback (most recent call last)
<ipython-input-7-2be8718c68ec> in <module>()
      7 x, n = symbols('x n')
      8 
----> 9 f = (cos(n*x))*(x**2-pi**2)^2
     10 integrate(f,(x,-n*pi,n*pi))
     11 

AttributeError: 'Mul' object has no attribute 'cos' 

我已经复制了下面的输入代码.谢谢你的帮助.

from pylab import *
from sympy import *
from numpy import *

init_printing(use_unicode=False, wrap_line=False, no_global=True)

x, n = symbols('x n')

f = (cos(n*x))*(x**2-pi**2)^2
integrate(f,(x,-n*pi,n*pi))

我试图使用Python2.7在数值上解决一个等式.这是整个代码:

from sympy import *
from sympy import Symbol
from sympy.solvers import nsolve
from scipy import *
from pylab import *
import numpy as np

# Symbols
theta = Symbol('theta')
phi = Symbol('phi')
phi0 = Symbol('phi0')
H0 = Symbol('H0')
# Constants
a = 0.05 
b = 0.05**2/(8*pi*1e-7)
c= 0.001/(4*pi*1e-7)
phi0 = 60*pi/180 
H0 = -0.03/(4*pi*1e-7)
def m(theta,phi):
    return np.array([sin(theta)*cos(phi), sin(theta)*cos(phi), cos(phi)])
def h(phi0):
    return np.array([cos(phi0), sin(phi0), 0])
def k(theta,phi,phi0):
    return np.vdot(m(theta,phi),h(phi0))
def F(theta,phi,phi0,H0): 
    return -(a*H0)*k(theta,phi,phi0)+b*(cos(theta)**2)+c*(sin(2*theta)**2)+sin(theta)**4*sin(2*phi)**2
def F_phi(theta,phi,phi0,H0):
    return simplify(diff(F(theta,phi,phi0,H0),phi))
def …