相关疑难解决方法(0)

我有2个矩阵,我需要将它们相乘,然后打印每个单元格的结果.一旦一个单元格准备就绪,我需要打印它,但是例如我需要在单元格[2] [0]之前打印[0] [0]单元格,即使[2] [0]的结果已经准备好了.所以我需要按顺序打印它.所以我的想法是让打印机线程等待,直到multiplyThread通知它正确的单元格已准备好打印,然后printerThread将打印单元格并返回等待等等.

所以我有这个线程来进行乘法运算:

public void run() 
{
    int countNumOfActions = 0; // How many multiplications have we done
    int maxActions = randomize(); // Maximum number of actions allowed

    for (int i = 0; i < size; i++)
    {       
        result[rowNum][colNum] = result[rowNum][colNum] + row[i] * col[i];
        countNumOfActions++;
        // Reached the number of allowed actions
        if (countNumOfActions >= maxActions)
        {
            countNumOfActions = 0;
            maxActions = randomize();
            yield();
        }   
    }
    isFinished[rowNum][colNum] = true;
    notify();
}

打印每个单元格结果的线程:

public …