相关疑难解决方法(0)

我有一系列的哈希像这样:

 [{"testPARAM1"=>"testVAL1"}, {"testPARAM2"=>"testVAL2"}]

而我正在尝试将此映射到单个哈希,如下所示:

{"testPARAM2"=>"testVAL2", "testPARAM1"=>"testVAL1"}

我已经实现了它

  par={}
  mitem["params"].each { |h| h.each {|k,v| par[k]=v} } 

但我想知道是否有可能以更惯用的方式做到这一点(最好不使用局部变量).

我怎样才能做到这一点？

给出以下哈希:

{"7"=>"Ada (gnat-4.3.2)", "13"=>"Assembler (nasm-2.07)", "45"=>"Assembler (gcc-4.3.4)", "104"=>"AWK (gawk) (gawk-3.1.6)", "105"=>"AWK (mawk) (mawk-1.3.3)", "28"=>"Bash (bash 4.0.35)", "110"=>"bc (bc-1.06.95)", "12"=>"Brainf**k (bff-1.0.3.1)", "11"=>"C (gcc-4.3.4)", "27"=>"C# (mono-2.8)", "1"=>"C++ (gcc-4.3.4)", "44"=>"C++0x (gcc-4.5.1)", "34"=>"C99 strict (gcc-4.3.4)", "14"=>"CLIPS (clips 6.24)", "111"=>"Clojure (clojure 1.1.0)", "118"=>"COBOL (open-cobol-1.0)", "106"=>"COBOL 85 (tinycobol-0.65.9)", "32"=>"Common Lisp (clisp) (clisp 2.47)", "102"=>"D (dmd) (dmd-2.042)", "36"=>"Erlang (erl-5.7.3)", "124"=>"F# (fsharp-2.0.0)", "123"=>"Factor (factor-0.93)", "125"=>"Falcon (falcon-0.9.6.6)", "107"=>"Forth (gforth-0.7.0)", "5"=>"Fortran (gfortran-4.3.4)", "114"=>"Go (gc-2010-07-14)", "121"=>"Groovy (groovy-1.7)", "21"=>"Haskell (ghc-6.8.2)", "16"=>"Icon (iconc 9.4.3)", "9"=>"Intercal (c-intercal 28.0-r1)", "10"=>"Java (sun-jdk-1.6.0.17)", "35"=>"JavaScript (rhino) (rhino-1.6.5)", "112"=>"JavaScript …

我有一个阵列

["bob:12 elm st", "sally:100 digital ave", "tom:2324 elmhurst st"] 

我需要转换为

{"bob" => "12 elm st", "sally" => "100 digital ave", "tom" => "2324 elmhurst st"}.

我知道我能做到

array.each do |e|
  k = e.split(":").first
  v = e.split(":").last
  hash[k] = v
end

有没有更优雅的方式来做到这一点？