我有动力使用pandas rolling功能来执行滚动多因素回归(这个问题不是关于滚动多因素回归).我希望我能够apply在a之后使用df.rolling(2)并将得到的pd.DataFrame提取物与ndarray一起使用.values并执行必要的矩阵乘法.它没有那么成功.
这是我发现的:
import pandas as pd
import numpy as np
np.random.seed([3,1415])
df = pd.DataFrame(np.random.rand(5, 2).round(2), columns=['A', 'B'])
X = np.random.rand(2, 1).round(2)
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对象是什么样的:
print "\ndf = \n", df
print "\nX = \n", X
print "\ndf.shape =", df.shape, ", X.shape =", X.shape
df =
A B
0 0.44 0.41
1 0.46 0.47
2 0.46 0.02
3 0.85 0.82
4 0.78 0.76
X =
[[ 0.93]
[ 0.83]]
df.shape = (5, …Run Code Online (Sandbox Code Playgroud) 我有一个包含 4 列的大型数据框 df:
id period ret_1m mkt_ret_1m
131146 CAN00WG0 199609 -0.1538 0.047104
133530 CAN00WG0 199610 -0.0455 -0.014143
135913 CAN00WG0 199611 0.0000 0.040926
138334 CAN00WG0 199612 0.2952 0.008723
140794 CAN00WG0 199701 -0.0257 0.039916
143274 CAN00WG0 199702 -0.0038 -0.025442
145754 CAN00WG0 199703 -0.2992 -0.049279
148246 CAN00WG0 199704 -0.0919 -0.005948
150774 CAN00WG0 199705 0.0595 0.122322
153318 CAN00WG0 199706 -0.0337 0.045765
id period ret_1m mkt_ret_1m
160980 CAN00WH0 199709 0.0757 0.079293
163569 CAN00WH0 199710 -0.0741 -0.044000
166159 CAN00WH0 199711 0.1000 -0.014644
168782 CAN00WH0 199712 …Run Code Online (Sandbox Code Playgroud)