相关疑难解决方法(0)

我了解到,当您在Java中修改变量时,它不会更改它所基于的变量

int a = new Integer(5);
int b = a;
b = b + b;
System.out.println(a); // 5 as expected
System.out.println(b); // 10 as expected

我假设对象有类似的东西.考虑这个课程.

public class SomeObject {
    public String text;

    public SomeObject(String text) {
        this.setText(text);
    }

    public String getText() {
        return text;
    }   

    public void setText(String text) {
        this.text = text;
    }
}

在我尝试这段代码后,我感到困惑.

SomeObject s1 = new SomeObject("first");
SomeObject s2 = s1;
s2.setText("second");
System.out.println(s1.getText()); // second as UNexpected
System.out.println(s2.getText()); // second as expected

请向我解释为什么更改任何对象会影响另一个对象.我知道变量文本的值存储在两个对象的内存中的相同位置.

为什么变量的值是独立的但与对象相关？

另外,如果简单的赋值不能完成工作,如何复制SomeObject？

public class DrumKitTestDrive {
/**
 * @param args
 */
public static void main(String[] args) {
    // TODO Auto-generated method stub
    Echo e1 = new Echo();
    Echo e2 = new Echo();
//      **e2 = e1;**

    int x=0;
    while( x < 4 ){
        e1.hello();
        e1.count = e1.count + 1;
        if(x==3){
            e2.count = e2.count + 1;
        }
        if(x>0){
            e2.count = e2.count + e1.count;
        }
        x = x + 1;
    }
    System.out.print(e2.count);
    }
}

class Echo {
    int  count = 0;

    void hello(){
        System.out.println("Hellooooo...."); …