当用户点击片段内的按钮时,我正在尝试显示Toast消息.问题是我无法访问活动以显示其上的Toast.
这是以下来源Fragment:
public class FrgTimes extends Fragment
{
ScrollView sv;
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState)
{
if (container == null) { return null; }
sv = (ScrollView)inflater.inflate(R.layout.frg_times, container, false);
btnTime1.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
//****** HERE's the PROBLEM ********
Toast.makeText(<The Activity>, "Please long press the key", Toast.LENGTH_LONG );
}});
return sv;
}
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这是我一直在尝试的.
Toast.makeText( getActivity() , ...
Toast.makeText( getView().getContext() , ...
Toast.makeText( getActivity().getApplicationContext() , ...
Toast.makeText( sv.getContext() , ...
Toast.makeText( sv.getRootView().getContext() , …Run Code Online (Sandbox Code Playgroud) 我有一个片段,允许用户输入消息和电话号码,消息将被传递到该消息.我收到一个错误"无法解析方法getApplicationContext()"我已经看到了答案这里方法getApplicationContext()未定义但它没有帮助我,也许我实现它错了但我不确定!此代码作为活动可以正常工作,但不能作为片段.
FragmentTab1类
package com.androidbegin.absfragtabhost;
import android.content.Context;
import android.os.Bundle;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.app.Fragment;
import android.app.Activity;
import android.telephony.SmsManager;
import android.util.Log;
import android.view.Menu;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;
public class FragmentTab3 extends Fragment {
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View rootView = inflater.inflate(R.layout.fragmenttab3, container, false);
super.onCreate(savedInstanceState);
//setContentView(R.layout.activity_main);
sendBtn = (Button) rootView.findViewById(R.id.btnSendSMS);
txtphoneNo = (EditText) rootView.findViewById(R.id.editTextPhoneNo);
txtMessage = (EditText) rootView.findViewById(R.id.editTextSMS);
sendBtn.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
sendSMSMessage();
} …Run Code Online (Sandbox Code Playgroud)