相关疑难解决方法(0)

template <size_t size, typename ...Params>
void doStuff(Params...) {
}

template <>
void doStuff<size_t(1), int, bool>(int, bool) {

}

int main(int, char**) {
    doStuff<1,int,bool>(1, false);
    return 0;
}

这不会编译,第二个doStuff声明给了我,error: template-id ‘doStuff<1u, int, bool>’ for ‘void doStuff(int, bool)’ does not match any template declaration但它明确地将第一个声明与variadic模板参数匹配.

如何专门研究可变参数模板？

使用旧版本的g ++(4.8.0,MinGW)编译项目我发现此代码无法编译:

template<typename T>
void foo() = delete;

template<>
void foo<int>(){}

int main() {
    foo<int>();
    return 0;
}

似乎g ++甚至没有尝试寻找显式特化,如果它看到基本情况被删除.

mitalia@mitalia:~/scratch$ /opt/mingw32-dw2/bin/i686-w64-mingw32-g++ -std=c++11 buggy_deleted_template.cpp 
buggy_deleted_template.cpp: In function 'int main()':
buggy_deleted_template.cpp:8:14: error: use of deleted function 'void foo() [with T = int]'
     foo<int>();
              ^
buggy_deleted_template.cpp:5:6: error: declared here
 void foo<int>(){}
      ^
mitalia@mitalia:~/scratch$ /opt/mingw32-dw2/bin/i686-w64-mingw32-g++ --version 
i686-w64-mingw32-g++ (rubenvb-4.8.0) 4.8.0
Copyright (C) 2013 Free Software Foundation, Inc.
This is free software; see the source for copying conditions.  There is NO
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