相关疑难解决方法(0)

AM在我的带有WAMP服务器的Windows PC上使用MySQL 5.7.13

这里我的问题是在执行此查询时

SELECT *
FROM `tbl_customer_pod_uploads`
WHERE `load_id` = '78' AND
      `status` = 'Active'
GROUP BY `proof_type`

我总是得到这样的错误

SELECT列表的表达式#1不在GROUP BY子句中,并且包含非聚合列'returntr_prod.tbl_customer_pod_uploads.id',它在功能上不依赖于GROUP BY子句中的列; 这与sql_mode = only_full_group_by不兼容

你能告诉我最好的解决方案吗？

我需要像结果一样

+----+---------+---------+---------+----------+-----------+------------+---------------+--------------+------------+--------+---------------------+---------------------+
| id | user_id | load_id | bill_id | latitude | langitude | proof_type | document_type | file_name    | is_private | status | createdon           | updatedon           |
+----+---------+---------+---------+----------+-----------+------------+---------------+--------------+------------+--------+---------------------+---------------------+
|  1 |       1 | 78      | 1       | 21.1212  | 21.5454   |          1 |             1 | id_Card.docx |          0 | Active | …

我有两个表:书籍和文章,它们之间有多对多的关系.加入表是BookArticles.

车型/ books.js

module.exports = function(sequelize, DataTypes) {
  return Food = sequelize.define("Book", {
    id: {
      type: DataTypes.INTEGER,
      primaryKey: true,
      allowNull: false,
      autoIncrement: true,
      unique: true
    }
  });
}

车型/ articles.js

module.exports = function(sequelize, DataTypes) {
  return Food = sequelize.define("Article", {
    id: {
      type: DataTypes.INTEGER,
      primaryKey: true,
      allowNull: false,
      autoIncrement: true,
      unique: true
    }
  });
}

车型/ bookArticles.js

module.exports = function(sequelize, DataTypes) {
  return Food = sequelize.define("BookArticles", {
    id: {
      type: DataTypes.INTEGER,
      primaryKey: true,
      allowNull: false,
      autoIncrement: true,
      unique: true
    }, …

Sequelize 版本：4.22.6，MySql 版本：5.7.8 我想在查询执行中在属性（在 _user_count_ 的位置）中“hasMany”关联（CompanyUser）计数

/**
* Company user associate with Company with belongsTo relation
*/
`CompanyUser.belongsTo(Company, { foreignKey: 'company_id', targetKey: 'id'});`

/**
* Company  associate with Company user with hasMany relation
*/
`Company.hasMany(CompanyUser, { foreignKey: 'company_id', sourceKey: 'id'});`

`return Company.findAll({
    attributes: [
        'id', 'title', 'is_enabled', '_user_count_'
    ]
    include: [
        {
            model: sqConn.CompanyUser,
            attributes: ['id'],
        },
        {
            model: sqConn.CompanyLogo,
            attributes:['file_object'],
        }
    ],
}).then(function(model) {
    return sequelize.Promise.resolve(model);
}).catch(function(err) {
    return sequelize.Promise.reject(err);
});`

带有左连接的简单 MySQL 查询工作正常并给出计数。

我正在尝试将此查询转换为序列化查询对象，正确的方法是什么？

SELECT families.id, count('answers.familyId') FROM families LEFT JOIN 
answers on families.id = answers.familyId WHERE answers.isActive=1 AND
answers.answer=1 GROUP BY families.id HAVING COUNT('answers.familyId')>=6