相关疑难解决方法(0)

_radixSort_0 = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
            0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
            0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
            0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
            0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
            0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
            0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
            0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
            0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
            0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
            0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
            0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
            0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
            0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
            0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
            0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0];
/*
RADIX SORT
Use 256 bins
Use shadow array
- Get counts
- Transform counts to pointers
- Sort from LSB - MSB
*/
function radixSort(intArr) {
    var cpy = new Int32Array(intArr.length);
    var c4 = [].concat(_radixSort_0); 
    var c3 = [].concat(_radixSort_0); 
    var c2 = [].concat(_radixSort_0);
    var c1 = [].concat(_radixSort_0); 
    var o4 = 0; var t4;
    var o3 = 0; var t3;
    var o2 …

在无序列表(例如100)中找到前N个(比如10个)元素的最佳解决方案是什么.

我头脑中的解决方案是1.使用快速排序对其进行排序,2.获得前10名.

但还有更好的选择吗？