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保留Rxjs生成的复选框的状态

基于在下拉列表中选择不同的项目,我生成带有复选框的项目的html.如何保留复选框的状态,即每当下拉列表中的值发生变化时选中/取消选中.请参阅此处的plunkr https://plnkr.co/edit/PUG3g7dfTbQjPyIgGLzh?p=preview

脚步:

- uncheck 'abc2'
- change dd value to 'international'
- again change the dd value to 'local'
- here 'abc2' must be unchecked...
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这是我的代码:

var data = [
    {type: 'local', name: 'abc1', location: 'xyz1', checked: true},
    {type: 'local', name: 'abc2', location: 'xyz2', checked: true},
    {type: 'international', name: 'abc3', location: 'xyz3', checked: true},
    {type: 'local', name: 'abc4', location: 'xyz4', checked: true},
    {type: 'local', name: 'abc5', location: 'xyz5', checked: true},
    {type: 'international', name: 'abc6', location: 'xyz6', checked: true},
    {type: …
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